如何在sequelize中選擇案例查詢？

Question

我有一個SQL查詢：

SELECT field1, field2,
  CASE
    WHEN field1=1 THEN 'a'
    ELSE 'b'
  END 
  AS field3
FROM test

我想用sequelizejs實現它，

const params = {
  attributes: //DO SELECT CASE,
};

yield Model.findAll(params);

誰能幫我？ 謝謝。

Answer 1

對於仍在尋找這個答案的人們

Model.findAll({
  attributes: [[models.sequelize.literal('CASE WHEN "field1" = true THEN 55 ELSE 23 END'), 'field3']]
}

要么

Model.findAll({
  attributes: { include: [[models.sequelize.literal('CASE WHEN "field1" = true THEN 55 ELSE 23 END'), 'field3']]}
}

所以在我的例子中，當field1為true時，它將返回55 else 23.這將生成一個類似的查詢

SELECT CASE WHEN "field1" THEN 55 ELSE 23 END AS "field3" FROM "models"

有關詳細信息，請參閱文檔http://docs.sequelizejs.com/en/latest/docs/querying/#attributes