[英]no operator matches || these operands
嗨,我在C ++中使用if語句遇到麻煩。 編譯代碼時,出現錯誤,指出“沒有運算符“ ||”與這些操作數匹配。 有什么猜想嗎? 該項目是我在Visual Studio中創建的一款基於文本的小型游戲。
#include "stdafx.h"
#include <iostream>
#include <iomanip>
#include <string>
#include <cmath>
#include <fstream>
using namespace std;
//Prototypes
void introScreen(int);
string characterCreation(string);
int choice;
string characterName, wepon1, wepon2, bow, sword, mace;
const string sword = sword;
const string bow = bow;
const string mace = mace;
// Functions
int main()
{
introScreen(choice);
return 0;
}
void introScreen(int choice)
{
cout << "----------------------------------------\n"
<< "Welcome to the arena!\n"
<< "Select a menu option\n"
<< "-----------------------------------------\n"
<< "1. New Game\n"
<< "2. Load\n"
<< "3. Exit\n\n"
<< "Enter your desired number ";
cin >> choice;
if (choice == 1)
characterCreation(characterName);
else
if (choice == 2)
exit(0);
else
if (choice == 3)
exit(1);
}
string characterCreation(string characterName,string wepon1,string wepon2, const string bow, const string sword, const string mace)
{
cout << "Welcome to the character creation menu!\n"
<< "Enter your name\n"
<< "Name: ";
cin.ignore();
getline(cin, characterName);
ofstream loadFile("Save.txt");
loadFile << characterName << endl;
cout << "\nEnter 2 wepons\n"
<< "Wepon list\n\n"
<< "Sword\n"
<< "Mace\n"
<< "Bow\n";
cin >> wepon1, wepon2;
if (wepon1 || wepon2 != bow || sword || mace)
{
cout << "\n\nThose wepons are invalid! Enter new ones\n";
cout << "\nEnter 2 wepons\n"
<< "Wepon list\n\n"
<< "sword\n"
<< "mace\n"
<< "bow\n";
cin >> wepon1, wepon2;
}
loadFile << wepon1 << endl
<< wepon2 << endl;
return characerName;
}
“ ||” 運算符是對邏輯條件的評估,您正在要求它評估字符串類型。 通常,在評估字符串值時,它們的評估方式就好像(weapon1!=“”)然后...
另外,請注意如何設置該值。 字符串值在雙引號內傳遞。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.