[英]Get the less count id's PandaCode as the output
請幫我解決這個問題我希望得到更小的PandaCode
作為輸出,我有一個PandaCode
Array
(
[0] => 37860
[1] => 37016
[2] => 37013
[3] => 38220
[4] => 38420
[5] => 38223
)
每個PandaCode
代碼已經多個id
S表示例如37860
有計數(ID)= 3這樣每個Pandacode
具有id
具有不同值的計數,但我想獲得PandaCode
其具有小於計數id
作為輸出
foreach($pandacode as $dealer_code){
$query="SELECT COUNT(id) FROM `dealer_details`
WHERE `PandaCode` like '$dealer_code' and `Senttime` like '%$today%'";
$result=mysqli_query($conn,$query);
$row = $result->fetch_assoc();
$size = $row['COUNT(id)'];
}
如果我以正確的方式理解你的問題,而不是添加whereIn而不是每個,請試試這個
SELECT COUNT(id) as ids FROM `dealer_details` WHERE `PandaCode` IN ($pandacode) and `Senttime` like '%$today%' GROUP BY `PandaCode` ORDER BY ids ASC LIMIT 1
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