[英]Passing multiple parameters in ajax is giving me error
我想將多個參數傳遞給我的ajax
代碼。 這是3
參數。 所以,我添加如下
$(document).ready(function () {
SearchText();
});
function SearchText() {
$("#txt712").autocomplete({
source: function (request, response) {
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "FrmAgreementMaster.aspx/GetAutoCompleteData",
//data: "{'username':'" + extractLast(request.term) + "'}",
data: JSON.stringify("{'username':'" + extractLast(request.term) + "'}", "{'taluka':'" + document.getElementById('ddlTaluka').value + "'}", "{'village':'" + document.getElementById('ddlVillage').value + "'}"),
dataType: "json",
success: function (data) {
response(data.d);
},
error: function (result) {
alert("Error");
}
});
},
focus: function () {
return false;
},
select: function (event, ui) {
var terms = split(this.value);
terms.pop();
terms.push(ui.item.value);
terms.push("");
this.value = terms.join(", ");
return false;
}
});
$("#txt712").bind("keydown", function (event) {
if (event.keyCode === $.ui.keyCode.TAB &&
$(this).data("autocomplete").menu.active) {
event.preventDefault();
}
})
function split(val) {
return val.split(/,\s*/);
}
function extractLast(term) {
return split(term).pop();
}
}
從這里參考Darin's
代碼。
但它在調用函數時將我帶到ERROR
部分。 如何傳遞多個參數以使用它。
更新
另外,我從這里獲取了ajax參考
回復代碼: -
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
[WebMethod]
public static List<string> GetAutoCompleteData(string username, string taluka, string village)
{
List<string> result = new List<string>();
using (OracleConnection ObjPriCon = new OracleConnection(System.Configuration.ConfigurationManager.ConnectionStrings["OracleConn"].ToString()))
{
using (OracleCommand cmd = new OracleCommand("select distinct survey_area_7_12 FROM xxcus.xxacl_pn_farming_mst WHERE survey_area_7_12 " +
"LIKE '%' || :searchtext || '%' and taluka = '" + taluka + "' and village = '" + village + "'", ObjPriCon))
{
ObjPriCon.Open();
cmd.Parameters.AddWithValue(":searchtext", username.ToLower());
OracleDataReader dr = cmd.ExecuteReader();
if (dr.HasRows)
{
while (dr.Read())
{
result.Add(dr["survey_area_7_12"].ToString());
}
}
return result;
}
}
}
您可以傳遞多個參數:
$.ajax({
...
data: {
var1: val1,
var2: val2,
var3: val3,
var4: val4,
// and many more
}
...
});
如果你想傳遞一個數組,你可以使用'JSON.stringify'。
嘗試傳遞這樣的數據:
data: JSON.stringify([
{username: extractLast(request.term)},
{taluka: document.getElementById('ddlTaluka').value},
{village: document.getElementById('ddlVillage').value}
]),
或者像這樣:
data: {
username: extractLast(request.term),
taluka: document.getElementById('ddlTaluka').value,
village: document.getElementById('ddlVillage').value
},
您不需要多個對象,在對象中需要多個屬性
data: JSON.stringify({username: extractLast(request.term) , taluka: $('#ddlTaluka').val(), village:$('#ddlVillage').val()}),
Ps:不要忘記在頁面就緒時觸發自動完成,確保在這些輸入中有值
最簡單的方法是將包含數據鍵值對的對象分配給ajax調用的data屬性。
$.ajax({
type: 'POST',
url: url,
data: {
'name': $('#name').val(),
'email': $('#email').val(),
// so on...
}
})
然后您可以通過您在此處指定的名稱簡單地在郵寄請求中獲取它們。
請嘗試這樣做。
$.ajax({
type: "POST",
contentType: "application/json; charset=utf-8",
url: "FrmAgreementMaster.aspx/GetAutoCompleteData",
//data: "{'username':'" + extractLast(request.term) + "'}",
data: JSON.stringify({
username: extractLast(request.term),taluka:document.getElementById('ddlTaluka').value,village:document.getElementById('ddlVillage').value
}),
error: function (result) {
alert("Error");
}
});
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