[英]How can I pass multiple arguements from Django Template to View via URL?
我正在嘗試一件簡單的事情用戶單擊顯示的問題。 單擊該鏈接時,將輸入問題ID,並將其作為自變量傳遞以顯示相關的選擇。 要求用戶選擇一個選項,然后下一頁將顯示有多少人對該選項進行了投票(包括用戶當前的決定)。 我收到的錯誤是當我使用127.0.0.1:8000/polls/啟動應用程序時,它顯示了問題。 然后,當我單擊問題時,URL變為127.0.0.1:8000/polls/3/,這是正確的,因為3是問題ID。 因此,預計將顯示問題ID的選擇。 但是它沒有顯示。 錯誤是:
NoReverseMatch at /polls/3/
Reverse for 'results' with arguments '()' and keyword arguments '{'q_id': 3, 'c_test': 'May Be'}' not found. 1 pattern(s) tried: ['polls/(?P<q_id>[0-9]+)/(?P<c_test>\\w+)/results/$']
Request Method: GET
Request URL: http://127.0.0.1:8000/polls/3/
Django Version: 1.10.3
Exception Type: NoReverseMatch
Exception Value:
Reverse for 'results' with arguments '()' and keyword arguments '{'q_id': 3, 'c_test': 'May Be'}' not found. 1 pattern(s) tried: ['polls/(?P<q_id>[0-9]+)/(?P<c_test>\\w+)/results/$']
Exception Location: /home/usr/.local/lib/python3.5/site-packages/django/urls/resolvers.py in _reverse_with_prefix, line 392
Python Executable: /usr/bin/python3.5
Python Version: 3.5.2
我的代碼是:
views.py
class IndexView(generic.ListView):
template_name = "polls/index.html"
context_object_name = "latest_question_list"
model = Question
def get_queryset(self):
return Question.objects.filter(
pub_date__lte=timezone.now()
).order_by('-pub_date')[:5]
class DetailView(ListView):
model = Choice
context_object_name = "latest_choice_list"
template_name = "polls/detail.html"
def get_queryset(self):
print(self.args[0])
'''Return list of choices'''
return Choice.objects.filter(question_id=self.args[0])
# return Choice.objects.all()
def pollvote(request, q_id, c_test):
if c_test:
p = Choice.objects.filter(question_id=q_id).get(choice_test=c_test)
count = p.votes
count += 1
p.votes = count
p.save()
return HttpResponseRedirect('/polls/%s/%s/results/' % c_test, q_id)
detail.html(錯誤表示問題在href行上)
{% load staticfiles %}
<link rel="stylesheet" type="text/css" href="{% static 'polls/style.css' %}" />
{% if latest_choice_list %}
<p>Cast your Choice</p>
<ul>
{% for choice in latest_choice_list %}
<li><a href="{% url 'polls:results' q_id=choice.question_id c_test=choice.choice_test%}">{{ choice.choice_test }}</a></li>
{% endfor %}
</ul>
{% else %}
<p>No choice are available.</p>
{% endif %}
results.html:
{% load staticfiles %}
<link rel="stylesheet" type="text/css" href="{% static 'polls/style.css' %}" />
{% if latest_choice_list %}
<p>Choices Made So Far</p>
<ul>
{% for choice in latest_choice_list %}
<li>{{ choice.choice_test }} - {{ choice.votes }} </li>
{% endfor %}
</ul>
{% else %}
<p>No choice are available.</p>
{% endif %}
urls.py
urlpatterns = [
url(r'^$', views.IndexView.as_view(), name='index'),
url(r'^([0-9]+)/$', views.DetailView.as_view(), name='detail'),
url(r'^(?P<q_id>[0-9]+)/(?P<c_test>\w+)/results/$', views.pollvote, name='results'),]
為什么detail.html拋出錯誤? 為什么不采用名為爭論的兩個關鍵字並將其傳遞給結果?
嘗試這個:
<a href="{% url 'polls:results' choice.question_id choice.choice_test%}">{{ choice.choice_test }}</a>
Django將按照給定的順序自動分配args。
聚苯乙烯
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