[英]Python - Create and instantiate class
我正在建立一class
播放列表,其中將包含許多相同類型的播放列表。
class playlist(object):
def __init__(self,name):
self.name = name
我想實例化他們通過用戶:
def hard_rock(self,user):
self.user = user
#query and retrieve data from music API
#return playlist
def pop_rock(self,user):
self.user = user
#query and retrieve data from music API
#return playlist
#and so on
創建實例:
r = playlist('rock')
r.hard_rock('user1')
這是建立和實例化類的邏輯方法嗎?
如果我理解正確,則需要播放列表和用戶
class Playlist(object):
def __init__(self, name):
self.name = name
self.liked_by = list()
@classmethod
def get_genre(cls, genre):
# this relies on no instance of this class
pass
# return api data...
class User(object):
def __init__(self, name):
self.name = name
def likes_playlist(self, playlist):
playlist.liked_by.append(self.name)
然后是一些例子
playlists = list()
hard_rock = Playlist('hard_rock')
joe = User('joe')
joe.likes_playlist(hard_rock)
playlists.append(hard_rock)
playlists.append(Playlist('pop_rock'))
country = Playlist.get_genre('country')
如果播放列表是應用程序的核心組件(使用類繼承的非常簡單的示例),則可能會發生這種情況。
>>> class playlist:
... def __init__(self,name, user):
... self.name = name
... self.user = user
...
>>> class hardrock(playlist):
... def __init__(self,name, user):
... playlist.__init__(self, name, user)
...
>>> test = hardrock('my_awesome_hardrock_list', 'my_awesome_username')
>>> print test.name
my_awesome_hardrock_list
>>> print test.user
my_awesome_username
您可以開始僅為用戶使用字符串,然后將其替換為實際對象,並在播放列表和用戶之間添加某種關系。 有關更多想法,請參閱cricket_007的建議。
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