[英]SQL - count over partition
請告訴我這有什么問題:
select
p.date,
(SELECT COUNT (*) OVER (PARTITION BY p.ID_code)
FROM POOL_AREA.F_volume_GCOA p
WHERE p.end_volume_KN <> 0
AND p.date = '31-OCT-16'
AND (p.local_grade_MB IS NULL OR p.local_grade_MB ='0' OR p.local_grade_MB ='N')) AS ERROR_CNT
FROM POOL_AREA.F_volume_GCOA p
where p.date = '31-OCT-16';
過度分區部分是問題,沒有它,它可以工作。
錯誤詳情:
ORA-01427: 單行子查詢返回多於一行
01427. 00000 - “單行子查詢返回多於一行”
*原因:
*行動:
我認為你真正追求的是一個有條件的計數——比如:
select p.dt,
count(case when p.end_volume_kn != 0
and (p.local_grade_mb is null
or p.local_grade_mb in ('0', 'N'))
then 1
end) error_cnt
FROM POOL_AREA.F_volume_GCOA p
where p.dt = to_date('31/10/2016', 'dd/mm/yyyy')
group by p.dt;
如評論中所述,類似這樣(未測試):
select
p.date,
t.val AS ERROR_CNT
FROM POOL_AREA.F_volume_GCOA p
JOIN (SELECT p.ID_code, COUNT (*) as val OVER (PARTITION BY p2.ID_code)
FROM POOL_AREA.F_volume_GCOA p2
WHERE p2.end_volume_KN <> 0
AND p2.date = '31-OCT-16'
AND (p2.local_grade_MB IS NULL OR p2.local_grade_MB ='0'
OR p.local_grade_MB ='N')) as t ON t.ID_Code = p.ID_code
where p.date = '31-OCT-16';
這有效!
select
p.date,
(SELECT COUNT (*) FROM
(SELECT DISTINCT p.id_code
FROM POOL_AREA.F_volume_GCOA p
WHERE p.end_volume_KN <> 0
AND p.date = '31-OCT-16'
AND (p.local_grade_MB IS NULL OR p.local_grade_MB ='0' OR p.local_grade_MB ='N'))) AS ERROR_CNT
FROM POOL_AREA.F_volume_GCOA p
where p.date = '31-OCT-16';
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