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SQL - 分區計數

[英]SQL - count over partition

請告訴我這有什么問題:

 select 
 p.date,
 (SELECT COUNT (*) OVER (PARTITION BY p.ID_code)
 FROM POOL_AREA.F_volume_GCOA p
 WHERE p.end_volume_KN <> 0
 AND p.date                = '31-OCT-16'
 AND (p.local_grade_MB IS NULL OR p.local_grade_MB ='0' OR          p.local_grade_MB ='N')) AS ERROR_CNT
 FROM POOL_AREA.F_volume_GCOA p
 where p.date                = '31-OCT-16';

過度分區部分是問題,沒有它,它可以工作。

錯誤詳情:
ORA-01427: 單行子查詢返回多於一行
01427. 00000 - “單行子查詢返回多於一行”
*原因:
*行動:

我認為你真正追求的是一個有條件的計數——比如:

select   p.dt,
         count(case when p.end_volume_kn != 0
                         and (p.local_grade_mb is null
                              or p.local_grade_mb in ('0', 'N'))
                         then 1
               end) error_cnt
FROM     POOL_AREA.F_volume_GCOA p
where    p.dt = to_date('31/10/2016', 'dd/mm/yyyy')
group by p.dt;

如評論中所述,類似這樣(未測試):

select 
 p.date,
 t.val AS ERROR_CNT    

 FROM POOL_AREA.F_volume_GCOA p
 JOIN (SELECT p.ID_code, COUNT (*) as val  OVER (PARTITION BY p2.ID_code)
 FROM POOL_AREA.F_volume_GCOA p2
 WHERE p2.end_volume_KN <> 0
 AND p2.date                = '31-OCT-16'
 AND (p2.local_grade_MB IS NULL OR p2.local_grade_MB ='0' 
     OR  p.local_grade_MB ='N')) as t ON t.ID_Code = p.ID_code
 where p.date                = '31-OCT-16';

這有效!

 select 
 p.date,
 (SELECT COUNT (*) FROM
(SELECT DISTINCT p.id_code
 FROM POOL_AREA.F_volume_GCOA p
 WHERE p.end_volume_KN <> 0
AND p.date                = '31-OCT-16'
AND (p.local_grade_MB IS NULL OR p.local_grade_MB ='0' OR              p.local_grade_MB ='N'))) AS ERROR_CNT
FROM POOL_AREA.F_volume_GCOA p
 where p.date                = '31-OCT-16';

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