[英]Jackson enum deserialization. Spring restTemplate
我在我的一個類中添加了一個枚舉類型和變量。 編寫一個使用此類的spring boot測試。
一旦添加了枚舉, jacksonMapper
就無法轉換類(用於restTemplate
POST請求)。
這是錯誤:
2016-11-17 11:36:11.571 WARN 10000 --- [o-auto-1-exec-1] .w.s.m.s.DefaultHandlerExceptionResolver : Failed to read HTTP message: org.springframework.http.converter.HttpMessageNotReadableException: Could not read document: Can not construct instance of com.springapp.models.common.Condo: no suitable constructor found, can not deserialize from Object value (missing default constructor or creator, or perhaps need to add/enable type information?)
at [Source: java.io.PushbackInputStream@6393fabb; line: 1, column: 2]; nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not construct instance of com.springapp.models.common.Condo: no suitable constructor found, can not deserialize from Object value (missing default constructor or creator, or perhaps need to add/enable type information?)
at [Source: java.io.PushbackInputStream@6393fabb; line: 1, column: 2]
2016-11-17 11:36:11.639 INFO 10000 --- [ main] c.s.controllers.api.CondoControllerTest : status: 400
2016-11-17 11:36:11.639 INFO 10000 --- [ main] c.s.controllers.api.CondoControllerTest : message: Could not read document: Can not construct instance of com.springapp.models.common.Condo: no suitable constructor found, can not deserialize from Object value (missing default constructor or creator, or perhaps need to add/enable type information?)
at [Source: java.io.PushbackInputStream@6393fabb; line: 1, column: 2]; nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not construct instance of com.springapp.models.common.Condo: no suitable constructor found, can not deserialize from Object value (missing default constructor or creator, or perhaps need to add/enable type information?)
at [Source: java.io.PushbackInputStream@6393fabb; line: 1, column: 2]
班級:
public class Condo {
**irrelevant fields**
public Condo(LocationType locationType) {
this.locationType = locationType;
}
public enum LocationType {
CONDO("condo"), MALL("mall"), STATION("station");
private String value;
private LocationType(String value) {
this.value = value;
}
public String stringValue() {
return this.value;
}
}
public LocationType getLocationType() {
return locationType;
}
LocationType locationType;
** getters/setters**
}
我也嘗試使用@JsonCreator, @jsonValue
因為它指向其他一些SO線程。 沒有幫助,
請求:
Condo condo = new Condo(Condo.LocationType.CONDO);
** setting fields for condo object **
//CREATE
ResponseEntity<JsonResponse> responseEntity = restTemplate.postForEntity(controllerPath+"/add_active", condo, JsonResponse.class);
如果您沒有Condo
作為輸入參數,請檢查您的控制器代碼。 從日志看來似乎如此。 Jackson無法反序列化Condo
的HTTP表示,因為它沒有默認構造函數。
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