[英]php json decode weird format
我正在嘗試從IP警報系統解碼一些數據。 有人告訴我數據是json,通過html文件查看,有對json的引用。 問題是它看起來有點怪:-)
這是警報的原始輸出:
/*-secure- { senrows : [ {no : "1", type : "Door Contact", zone : "1", name : "zone1", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "2", type : "Door Contact", zone : "2", name : "zone2", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "3", type : "Door Contact", zone : "3", name : "zone3", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "4", type : "Door Contact", zone : "4", name : "zone4", attr : "Burglar", cond : "", battery : "Low", tamp : "", bypass : "No"}, {no : "5", type : "Door Contact", zone : "5", name : "zone5", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "6", type : "Door Contact", zone : "6", name : "zone6", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "7", type : "Door Contact", zone : "7", name : "zone7", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "8", type : "Door Contact", zone : "8", name : "zone8", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "9", type : "Door Contact", zone : "9", name : "zone9", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "10", type : "IR Sensor", zone : "10", name : "zone10", attr : "Burglar", cond : "", battery : "Low", tamp : "", bypass : "No"}, {no : "11", type : "Remote Keypad", zone : "11", name : "zone11", attr : "",cond : "", battery : "", tamp : "", bypass : "No"}] } */
如何解碼此數據? :-)
json_decode()不起作用:-/
好了,無論誰給您此輸出,您都應該始終首先要求他們修復代碼並實際提供JSON。
仍然,我花了幾分鍾時間,享受了編碼練習,為您的數據編寫了一個快速修復程序。
僅當您的代碼始終以相同的-secure-
開頭時,它才起作用,否則您必須對其進行調整。
並且如果由於某種原因您有一個帶有封裝字符串的字段(例如a:"text\\"moretext\\"finaltext"
,或者提供者除示例中顯示的錯誤之外引入了其他錯誤, 它將失敗或產生奇怪的結果。
<?php
$data = /*your not-JSON-string*/;
function fix_botched_json($data) {
//remove comment-section, we don't need it
$data = substr($data, 10, strlen($data)-12);
$seek = '/(\w+)/';
$exploded = explode('"', $data);
//explode so we only replace *outside* of strings
$outside = true;
foreach($exploded as &$item) {
if($outside) {
//the regex matches only word characters.
$item = preg_replace($seek, '"\1"', $item);
}
//alternating between inside and outside of strings
$outside = !$outside;
}
//piece it back together
$imploded = implode('"', $exploded);
return $imploded;
}
$final = json_decode(fix_botched_json($data), true);
非常棘手的解決方案,不保證與您可能擁有的其他字符串一起使用。 有很多方法可以處理這種情況,最好的方法可能是要求警報系統的創建者開始生成有效的JSON!
<?php
$string = '/*-secure- { senrows : [ {no : "1", type : "Door Contact", zone : "1", name : "zone1", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "2", type : "Door Contact", zone : "2", name : "zone2", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "3", type : "Door Contact", zone : "3", name : "zone3", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "4", type : "Door Contact", zone : "4", name : "zone4", attr : "Burglar", cond : "", battery : "Low", tamp : "", bypass : "No"}, {no : "5", type : "Door Contact", zone : "5", name : "zone5", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "6", type : "Door Contact", zone : "6", name : "zone6", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "7", type : "Door Contact", zone : "7", name : "zone7", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "8", type : "Door Contact", zone : "8", name : "zone8", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "9", type : "Door Contact", zone : "9", name : "zone9", attr : "Burglar", cond : "", battery : "", tamp : "", bypass : "No"}, {no : "10", type : "IR Sensor", zone : "10", name : "zone10", attr : "Burglar", cond : "", battery : "Low", tamp : "", bypass : "No"}, {no : "11", type : "Remote Keypad", zone : "11", name : "zone11", attr : "",cond : "", battery : "", tamp : "", bypass : "No"}] } */';
function fix_json($st){
$regex = '/([a-zA-Z0-9_]+)(\s)(?=:)/i';
return preg_replace($regex, '"$1"', $st);
}
$step1 = strstr($string, '{');
$step2 = rtrim($step1, '*/');
$data = fix_json($step2);
var_dump(json_decode($data, true));
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