從MySQL數據庫中預先選擇的下拉列表值

Question

盡管我已經進行了研究，但找不到任何解決方案。 我需要獲取數據庫值（“默認”）作為下拉列表的預選值。

<select name="listCustomer" id="listCustomer">
    <?php 
    $sql = mysqli_query($connection,"SELECT customer_name FROM customers");
    while ($row = mysqli_fetch_array($sql,MYSQLI_ASSOC)){
    echo "<option value=\"" .   $row['customer_name'] . "\">" . $row['customer_name'] . "</option>";}
    ?>
</select>

你能幫我嗎？

Answer 1

只需在回顯之前創建一個變量，例如：

$selected = ((strtolower($row['customer_name']) == 'default') ? 'selected' : '');

然后將回顯更改為此：

echo '<option '.$selected.' value="'.$row['customer_name'].'">'.$row['customer_name'].'</option>';

Answer 2

這可以通過在customer_name上使用if語句來完成

$sql = mysqli_query($connection,"SELECT customer_name FROM customers");
while ($row = mysqli_fetch_array($sql,MYSQLI_ASSOC)){
     if($row["customer_name"] === "Default"){
      echo "<option value=\"" .   $row['customer_name'] . "\" selected>" . $row['customer_name'] . "</option>";
     } else {
       echo "<option value=\"" .   $row['customer_name'] . "\">" . $row['customer_name'] . "</option>";
     }
 }
 ?>

注意第一個回聲上的選定標簽。

Answer 3

$query="SELECT customer_name FROM customers";
$result = @mysql_query ($query);
echo "<select name=customer_name value=' '>";
while($drop=@mysql_fetch_array($result)){
echo "<option value=$drop[customer_name]>$drop[customer_name]</option>";
}
echo "</select>";