[英]HTTP Status 404 — Spring MVC
我在tomcat 8.0.39上運行代碼,它首先顯示login.jsp,當我填寫名稱和密碼並點擊Submit時,它返回404錯誤:login.jsp圖片HTTP狀態404圖片
我的代碼如下:
web.xml
<!-- webapp/WEB-INF/web.xml -->
<web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
version="3.0">
<display-name>To do List</display-name>
<welcome-file-list>
<welcome-file>login.do</welcome-file>
</welcome-file-list>
</web-app>
LoginServlet.java
package com.ezmsip;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet(urlPatterns="/login.do")
public class LoginServlet extends HttpServlet {
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
request.getRequestDispatcher("WEB-INF/views/login.jsp").forward(request, response);
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
request.setAttribute("name", request.getParameter("name"));
request.getRequestDispatcher("WEB-INF/views/welcome.jsp").forward(request, response);
}
}
login.jsp的
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Hola desde una JSP</title>
</head>
<body>
<form action="/login.do" method="post">
Nombre: <input type="text" name="name" /> Password: <input type="password" name="password" /> <input type="submit" value="Log-in" />
</form>
</body>
</html>
welcome.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Bienvenido!</title>
</head>
<body>
Bienvenido! ${name}
</body>
</html>
謝謝!
它沒有抱怨login.jsp。 它抱怨/login.do
。 您是否將此應用程序部署為tomecat的根Web應用程序? 否則,它位於上下文路徑下,並且您需要執行類似/myWebApp/login.do
類的/myWebApp/login.do
。
無論如何,正確的做法是在上下文路徑前添加:
action="${pageContext.request.contextPath}/login.do"
或者,使用JSTL:
action="<c:url value='/login.do'/>"
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