使用PHP將圖像上傳到MySQL數據庫時出現問題
[英]Issue in uploading images to MySQL database using PHP
問題描述
我有此php代碼將圖像上傳到數據庫，但我有問題，我不知道它是什么，數據庫表名稱為images，字段為id ， name VARCHAR() ， photo LONGBLOB 。
<?php
ini_set('display_errors', '1');
$servername = "";
$username = "";
$password = "";
//$host = "";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
?>
<html>
<body>
<form method="post" enctype="multipart/form-data">
<input type="file" name="image"/>
</br>
</br>
</br>
<input type="submit" name="go" value="Upload"/>
</form>
<?php
if(isset($_POST['go'])){
if(getimagesize($_FILES['image']['tmp_name']) == FALSE){
echo "Select a photo please";
}else {
$image = addslashes($_FILES['image']['tmp_name']);
$name = addslashes($_FILES['image']['name']);
$image = file_get_contents($image);
$image = base64_encode($image);
save_image($image , $name);
}
}
function save_image($image , $name){
$servername = "localhost";
$username = "cl60-shooters";
$password = "dbsjcNs-b";
$conn = new mysqli($servername, $username, $password);
$qry = "insert into images (photo , name) VALUES ('$image','$name')";
$result = mysqli_query($conn,$qry);
if($result){
echo "Successfull upload";
}else{
echo "try Again";
print_r($result);
}
}
?>
</body>
</html>
結果如所附的屏幕快照所示： 結果
2 個解決方案
解決方案1
0 已采納 2016-11-27 13:18:48
您的函數忽略了提及數據庫-您需要將其作為參數之一提供，例如：
function save_image($image , $name){
$servername = "localhost";
$username = "cl60-shooters";
$password = "dbsjcNs-b";
$database='xxxxxxxx';/* enter correct db name */
$conn = new mysqli( $servername, $username, $password, $database );
$qry = "insert into images (`photo`, `name`) VALUES ('$image','$name')";
$result = mysqli_query($conn,$qry);
if($result){
echo "Successfull upload";
}else{
echo "try Again";
print_r($result);
}
}
僅供參考，您的代碼容易受到sql注入攻擊-最好使用准備好的語句！
解決方案2
0 2016-11-27 13:27:01
您沒有在mysqli構造函數中使用數據庫名稱。 它應如下所示：
$servername = "localhost";
$username = "cl60-shooters";
$password = "dbsjcNs-b";
$database = "database_name_here";
$conn = new mysqli($servername, $username, $password, $database);
希望它現在可以工作。
使用php在數據庫mysql中上傳圖像
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