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[英]Django - AttributeError: 'UserProfile' object has no attribute 'urls'
[英]Django AttributeError: 'Alias' object has no attribute 'urls'
我剛剛為我的 Heroes 應用編寫了我的模型:
這是我的 Heroes 應用程序的 models.py 文件:
從 django.db 導入模型
# Create your models here.
class Hero(models.Model):
codename = models.CharField(max_length = 30)
profilePic = models.ImageField(blank=True) #blank makes this optional
def __str__(self):
return (self.codename)
class Stats(models.Model):
heroID = models.ForeignKey('Hero')
height = models.CharField(max_length = 10)
weight = models.CharField(max_length = 10)
STATS_CHOICES = (
('1', 'Extremely Low'),
('2', 'Very Low'),
('3', 'Low'),
('4', 'Average'),
('5', 'Good'),
('6', 'Above Average'),
('7', 'High'),
('8', 'Very High'),
('9', 'Super Human'),
('10', 'Above and Beyond'))
powers = models.CharField(max_length = 5, choices = STATS_CHOICES)
intelligence = models.CharField(max_length = 5, choices = STATS_CHOICES)
durability = models.CharField(max_length = 5, choices = STATS_CHOICES)
strength = models.CharField(max_length = 5, choices = STATS_CHOICES)
speed = models.CharField(max_length = 5, choices = STATS_CHOICES)
def __str__(self):
return (self.heroID)
class Team(models.Model):
name = models.CharField(max_length = 25)
leader = models.IntegerField
address = models.TextField
description = models.TextField
members = models.TextField
class Status(models.Model):
heroID = models.ForeignKey('Hero')
missionID = models.IntegerField
TeamID = models.IntegerField
def __str__(self):
return (self.heroID, self.missionID, self.TeamID)
class Alias(models.Model):
heroID = models.ForeignKey('Hero')
firstName = models.CharField(max_length = 25)
surname = models.CharField(max_length = 25)
formerCodeNames = models.TextField
occupation = models.CharField(max_length = 30)
address = models.TextField
citizenship = models.CharField(max_length = 40)
species = models.CharField(max_length = 40)
def __str__(self):
return (self.heroID, self.firstName, self.surname)
我在已安裝的應用程序下調整了我的 settings.py 文件:
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
#custom apps
'heroes',
]
然后我調整了我的 admin.py 文件:
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register(Hero, Stats)
admin.site.register(Team)
admin.site.register(Status, Alias)
在命令提示符中,我輸入: python manage.py makemigrations 並且我收到此錯誤 - “AttributeError: 'Alias' object has no attribute 'urls'”:
(secondproject) C:\Python34\Scripts\secondproject\heroes4Hire>python manage.py
emigrations
aceback (most recent call last):
File "manage.py", line 22, in <module>
execute_from_command_line(sys.argv)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\__init__.py", line 367, in execute_from_command_line
utility.execute()
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\__init__.py", line 359, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 294, in run_from_argv
self.execute(*args, **cmd_options)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 342, in execute
self.check()
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 374, in check
include_deployment_checks=include_deployment_checks,
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 361, in _run_checks
return checks.run_checks(**kwargs)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
istry.py", line 81, in run_checks
new_errors = check(app_configs=app_configs)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
s.py", line 14, in check_url_config
return check_resolver(resolver)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
s.py", line 24, in check_resolver
for pattern in resolver.url_patterns:
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\utils\functi
l.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\urls\resolve
py", line 313, in url_patterns
patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\utils\functi
l.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\urls\resolve
py", line 306, in urlconf_module
return import_module(self.urlconf_name)
File "C:\Python34\Scripts\secondproject\lib\importlib\__init__.py", line 109,
import_module
return _bootstrap._gcd_import(name[level:], package, level)
File "<frozen importlib._bootstrap>", line 2254, in _gcd_import
File "<frozen importlib._bootstrap>", line 2237, in _find_and_load
File "<frozen importlib._bootstrap>", line 2226, in _find_and_load_unlocked
File "<frozen importlib._bootstrap>", line 1200, in _load_unlocked
File "<frozen importlib._bootstrap>", line 1129, in _exec
File "<frozen importlib._bootstrap>", line 1471, in exec_module
File "<frozen importlib._bootstrap>", line 321, in _call_with_frames_removed
File "C:\Python34\Scripts\secondproject\heroes4Hire\heroes4Hire\urls.py", lin
0, in <module>
url(r'^admin/', admin.site.urls),
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\contrib\admi
ites.py", line 267, in urls
return self.get_urls(), 'admin', self.name
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\contrib\admi
ites.py", line 251, in get_urls
url(r'^%s/%s/' % (model._meta.app_label, model._meta.model_name), include(m
l_admin.urls)),
tributeError: 'Alias' object has no attribute 'urls'
這是什么意思,我該如何解決? 我在 StackOverFlow 上看過其他類似的問題,但我不明白如何解決它。
我終於在 codebar 的聚會上得到了答案!
model.p 中的每個類都需要位於 admin.py 上的單獨一行中。
所以答案是:
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register(Hero)
admin.site.register(Stats)
admin.site.register(Team)
admin.site.register(Status)
admin.site.register(Alias)
你應該改變
admin.site.register(Status, Alias)
到
admin.site.register(Status)
admin.site.register(Alias)
此模型應通過單獨的行添加到 admin 中。
register 函數將一個類列表作為它的第一個參數
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register( [Hero, Stats, Team, Status, Alias] )
(tl;dr:將模型放在列表中)
有同樣的問題,在這里找到解決方案然后自己閱讀代碼並認為我會添加一些細節。
這是注冊函數的定義(來自 django/contrib/admin/sites.py)。
def register(self, model_or_iterable, admin_class=None, **options):
...
它需要一個模型或一個可迭代對象,它做的第一件事是檢查它是否有一個模型,如果有,把它放在一個列表中,然后在它上面運行主循環(第一行與那個無關):
admin_class = admin_class or ModelAdmin
if isinstance(model_or_iterable, ModelBase):
model_or_iterable = [model_or_iterable]
for model in model_or_iterable:
...
當您將第二個模型放在不在列表中時,它會被傳遞給 admin_class 參數並被視為這樣,直到最終在某處給出錯誤為止。
因此,您可以將所有模型放在一個列表中,而不是多次調用此函數。 我什至會用一個來做 - 無論如何,該函數都會這樣做,所以你只是為了避免自己和其他人在以后遇到這個問題而編輯代碼。
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