為什么我不能在任何方法外創建對象

Question

在編寫程序時，我遇到了一個方法外實例化的stackoverflow錯誤，因此我在Internet上搜索了該代碼，但我不了解任何合適的解決方案。

所以任何人都可以讓我擺脫混亂。 我正在使用聚合，因為它具有Has-a關系。下面是我的Mainpage.class，它將首先執行。

 import  java.util.Scanner;
public class Mainpage {
    Scanner in = new Scanner(System.in);
    People people;
public void openapp()
{
    people = new People();
    System.out.println("Welcome to the Chat");
    System.out.println();
    System.out.println("1. Newsfeed");
    System.out.println("2. Chat");
    System.out.println("3. Friends");
    System.out.println("Enter your choice");
    int input = in.nextInt();


    switch(input)
    {
    case 1:
        System.out.println("Newsfeed");
        break;
    case 2:
        System.out.println("Chat");
        break;
    case 3:
        System.out.println("Friends");
        break;
        default :
            System.out.println("Invalid Input");
    }
    if(input == 3)
    {
        people.friends();
    }
    }
public static void main(String args[]){
    Mainpage m = new Mainpage();
    m.openapp();
}
}

下面是我的People.class代碼，將從Mainpage類的輸入中選擇朋友時調用

import java.util.Scanner;
public class People{
    People ps = new People();
    Scanner input = new Scanner(System.in);
    public void friends()
    { 
        System.out.println("Your friends are");
        System.out.println();
        System.out.println("Amit");
        System.out.println("Rahul");
        System.out.println("Ankita");
        System.out.println("Enter the friend name to see info");
        String fr = input.nextLine();
        //ps.friend(fr);

        switch(fr){
        case "Amit": 
            System.out.println("Name: Amit");
            System.out.println("DOB: 09-02-1993");
            System.out.println("Age = 23");
            System.out.println("Sex: M");
            break;
        case "Rahul":
            System.out.println("Name: Rahul");
            System.out.println("DOB: 11-10-1993");
            System.out.println("Age = 23");
            System.out.println("Sex: M");
            break;
        case "Ankita":
            System.out.println("Name: Ankita");
            System.out.println("DOB: 12-03-1993");
            System.out.println("Age = 22");
            System.out.println("Sex: M");
            break;
        default:
            System.out.println("You have no one With name "+fr+" in your contact list");
            System.out.println("Please again select the friends form the lists");
            ps.friends();
        }

    }

我收到Stackoverflow錯誤，因此請清除我的疑問。

Exception in thread "main" java.lang.StackOverflowError
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)
        at People.<init>(People.java:4)

Answer 1

刪除People ps = new People(); 從您的People類中獲取，因為它將導致對People的構造函數的無限調用。

調用new People()將初始化實例變量，因此它將永遠遞歸調用People() 。