如何通過谷歌地圖iOS API對地址進行地理編碼？

Question

我找到了一種發送請求的方法：

Google Maps Geocoding API請求采用以下格式：

https://maps.googleapis.com/maps/api/geocode/outputFormat?parameters其中outputFormat可以是以下值之一：

json（推薦）表示JavaScript Object Notation（JSON）中的輸出; 或xml表示XML格式的輸出要通過HTTP訪問Google Maps Geocoding API，請使用：

但它真的很不方便，有什么本地方式在swift？

我查看了GMSGeocoder接口，只能通過它的API完成反向地理編碼。

Answer 1

正如其他人所指出的，沒有預定義的方法來進行搜索，但您可以使用網絡請求自行訪問Google地理編碼API ：

func performGoogleSearch(for string: String) {
    strings = nil
    tableView.reloadData()

    var components = URLComponents(string: "https://maps.googleapis.com/maps/api/geocode/json")!
    let key = URLQueryItem(name: "key", value: "...") // use your key
    let address = URLQueryItem(name: "address", value: string)
    components.queryItems = [key, address]

    let task = URLSession.shared.dataTask(with: components.url!) { data, response, error in
        guard let data = data, let httpResponse = response as? HTTPURLResponse, httpResponse.statusCode == 200, error == nil else {
            print(String(describing: response))
            print(String(describing: error))
            return
        }

        guard let json = (try? JSONSerialization.jsonObject(with: data)) as? [String: Any] else {
            print("not JSON format expected")
            print(String(data: data, encoding: .utf8) ?? "Not string?!?")
            return
        }

        guard let results = json["results"] as? [[String: Any]],
            let status = json["status"] as? String,
            status == "OK" else {
                print("no results")
                print(String(describing: json))
                return
        }

        DispatchQueue.main.async {
            // now do something with the results, e.g. grab `formatted_address`:
            let strings = results.compactMap { $0["formatted_address"] as? String }
            ...
        }
    }

    task.resume()
}

Answer 2

不，Google Maps SDK for iOS中沒有原生方式。

這是一個非常受歡迎的功能請求，請參閱： 問題5170：功能請求：轉發地理編碼（從地址到坐標）

Answer 3

如果您只是在尋找Geocoding解決方案，您可以查看我構建的一個小型開源項目。 它非常輕量級，使用名為Nominatim的OpenStreetMap地理編碼API。 在這里查看： https ： //github.com/caloon/NominatimSwift

你甚至可以搜索地標。

地理編碼地址和地標：

Nominatim.getLocation(fromAddress: "The Royal Palace of Stockholm", completion: {(error, location) -> Void in
  print("Geolocation of the Royal Palace of Stockholm:")
  print("lat = " + (location?.latitude)! + "   lon = " + (location?.longitude)!)
})

Answer 4

不幸的是，沒有辦法像原生那樣做。 我希望這個功能會有所幫助。

    func getAddress(address:String){

    let key : String = "YOUR_GOOGLE_API_KEY"
    let postParameters:[String: Any] = [ "address": address,"key":key]
    let url : String = "https://maps.googleapis.com/maps/api/geocode/json"

    Alamofire.request(url, method: .get, parameters: postParameters, encoding: URLEncoding.default, headers: nil).responseJSON {  response in

        if let receivedResults = response.result.value
        {
            let resultParams = JSON(receivedResults)
            print(resultParams) // RESULT JSON
            print(resultParams["status"]) // OK, ERROR
            print(resultParams["results"][0]["geometry"]["location"]["lat"].doubleValue) // approximately latitude
            print(resultParams["results"][0]["geometry"]["location"]["lng"].doubleValue) // approximately longitude
        }
    }
}

Answer 5

Alamofire和Google的Geodecode API

斯威夫特4

func getAddressFromLatLong(latitude: Double, longitude : Double) {
    let url = "https://maps.googleapis.com/maps/api/geocode/json?latlng=\(latitude),\(longitude)&key=YOUR_API_KEY_HERE"

    Alamofire.request(url).validate().responseJSON { response in
        switch response.result {
        case .success:

            let responseJson = response.result.value! as! NSDictionary

            if let results = responseJson.object(forKey: "results")! as? [NSDictionary] {
                if results.count > 0 {
                    if let addressComponents = results[0]["address_components"]! as? [NSDictionary] {
                        self.address = results[0]["formatted_address"] as? String
                        for component in addressComponents {
                            if let temp = component.object(forKey: "types") as? [String] {
                                if (temp[0] == "postal_code") {
                                    self.pincode = component["long_name"] as? String
                                }
                                if (temp[0] == "locality") {
                                    self.city = component["long_name"] as? String
                                }
                                if (temp[0] == "administrative_area_level_1") {
                                    self.state = component["long_name"] as? String
                                }
                                if (temp[0] == "country") {
                                    self.country = component["long_name"] as? String
                                }
                            }
                        }
                    }
                }
            }
        case .failure(let error):
            print(error)
        }
    }
}

Answer 6

您可以使用地方搜索 Google Places API通過地址的網址會話發送請求，然后解析json結果。 它可能不完美但你可以得到除坐標以外的更多信息。

Answer 7

Google Maps API iOS SDK中沒有原生方式。 正如其他答案中所提到的，它已成為多年來所要求的功能 。

需要記住的一點是，Google Maps API主要專注於創建地圖：這是主要目標。

您必須使用基於URL的API調用或其他一些服務。 例如，一個名為SmartyStreets的不同服務有一個iOS SDK，它支持前向地理編碼。 以下是來自iOS SDK文檔頁面的 Swift示例代碼：

// Swift: Sending a Single Lookup to the US ZIP Code API

package examples;

import Foundation
import SmartystreetsSDK

class ZipCodeSingleLookupExample {

    func run() -> String {
        let mobile = SSSharedCredentials(id: "SMARTY WEBSITE KEY HERE", hostname: "HOST HERE")
        let client = SSZipCodeClientBuilder(signer: mobile).build()
//        Uncomment the following line to use Static Credentials
//        let client = SSZipCodeClientBuilder(authId: "YOUR AUTH-ID HERE", authToken: "YOUR AUTH-TOKEN HERE").build()

        let lookup = SSZipCodeLookup()
        lookup.city = "Mountain View"
        lookup.state = "California"

        do {
            try client?.send(lookup)
        } catch let error as NSError {
            print(String(format: "Domain: %@", error.domain))
            print(String(format: "Error Code: %i", error.code))
            print(String(format: "Description: %@", error.localizedDescription))
            return "Error sending request"
        }

        let result: SSResult = lookup.result
        let zipCodes = result.zipCodes
        let cities = result.cities

        var output: String = String()

        if (cities == nil && zipCodes == nil) {
            output += "Error getting cities and zip codes."
            return output
        }

        for city in cities! {
            output += "\nCity: " + (city as! SSCity).city
            output += "\nState: " + (city as! SSCity).state
            output += "\nMailable City: " + ((city as! SSCity).mailableCity ? "YES" : "NO") + "\n"
        }

        for zip in zipCodes! {
            output += "\nZIP Code: " + (zip as! SSZipCode).zipCode
            output += "\nLatitude: " + String(format:"%f", (zip as! SSZipCode).latitude)
            output += "\nLongitude: " + String(format:"%f", (zip as! SSZipCode).longitude) + "\n"
        }

        return output
    }
}

完全披露：我曾在SmartyStreets工作過。