[英]Add Case Switch To PHP Array()
header('Content-Type: application/json');
$Y = 2017;
$UK_Holidays = array(
'New Year\'s Day' => array(
'start' => strtotime('30-12-'.$Y.' 00:00:00'),
'end' => strtotime('30-12-'.$Y.' 23:59:59'),
'type' => 'Bank holiday',
'Observed' => 'Default'
),
'2nd January (substitute day)' => array(
'start' => '',
'end' => '',
'type' => 'Local holiday',
'Observed' => 'Scotland'
),
);
echo json_encode($UK_Holidays, JSON_PRETTY_PRINT);
{
"New Year's Day": {
"start": 1514592000,
"end": 1514678399,
"type": "Bank holiday",
"Observed": "Default"
},
"2nd January (substitute day)": {
"start": "",
"end": "",
"type": "Local holiday",
"Observed": "Scotland"
}
}
我有更多的假期可以實現到此PHP腳本中,其中一些假期取決於另一個假期的到來日期。 在1月2日(替代日),我開發了一個開關盒;
1月2日(替換日)的PHP案例切換:
function calculateBankHolidays($Y) {
$bankHols = Array();
switch (date("w", strtotime("01-01-$Y 00:00:00"))) {
case 6:
$bankHols[] = "03-01-$Y";
break;
case 0:
$bankHols[] = "02-01-$Y";
break;
default:
$bankHols[] = "01-01-$Y";
}
return $bankHols;
}
輸出:
[
{
"New Year's": {
"Start Date": "02-01-2017"
}
}
]
將案例切換實現到PHP腳本中的最佳方法是什么?
strtotime
是您的朋友,結合了相關格式(請參閱http://php.net/manual/zh/datetime.formats.relative.php )。 您可以做類似的事情。
$year = date('Y');
$ts_Jan1 = strtotime("Jan 1 $year -1 day next weekday");
$ts_Jan2 = strtotime("next weekday", $ts_Jan1);
$ts2 = strtotime("first Monday Jan $year");
編輯:添加此PHPfiddle以顯示工作代碼。 此工作代碼生成的日期與OP提供的鏈接中表中的日期匹配: https : //www.timeanddate.com/holidays/uk/2nd-january
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.