Laravel查詢生成器原始表達式

Question

在這種情況下，如何使用查詢生成器在join子句中編寫原始表達式？

SELECT 
    rating.post_id,
    sum(rate_like), 
    sum(rate_dislike), 
    (sum(rate_like) + sum(rate_dislike)),
    column_rating
from rating
inner join (
    select 
        post_id, 
        round(round((((sum(rate_like) / (sum(rate_like) + sum(rate_dislike)) * 100) * 0.5) / 10) * 2) / 2, 1) as column_rating
    from rating group by post_id
) as rating_table
on rating.post_id = rating_table.post_id
group by rating.post_id

我嘗試通過以下方式實現它，但是它不起作用：

DB::table('db_test')->table('rating')
                     ->join('rating_table', 'select ... from rating as rating_table')
                     ->raw('rating.post_id,
                            sum(rate_like), 
                            sum(rate_dislike), 
                            (sum(rate_like) + sum(rate_dislike)),
                            column_rating')

Answer 1

我能夠使用->join(DB()->raw('select...')