[英]pretty-print C++ containers with indent by level
這是Kerrek SB等人先前關於漂亮打印STL容器的問題的后續文章, Pretty-print C ++ STL容器 ,Kerrek等成功地為其開發了一個非常優雅且完全通用的解決方案,以及其后續版本Pretty-print std ::元組 ,其中處理std::tuple<Args...>
。
我想知道是否有可能采用縮進的解決方案?
例如,如果我有一個向量,一個向量,一個向量,一個字符串向量,我想看一下類似的東西:
{ // vector of vector of vector of string
{ // vector of vector of string
{ hello, world };// vector of string
{ The, quick, brown, fox, jumps, over, the, lazy, dog };
...
{ Now, is, the, time, for, all, good, men, to, come, to, the, aid, of, the, party}
};
{ // vector of vector of string
{ hello, world };// vector of string
{ The, quick, brown, fox, jumps, over, the, lazy, dog };
...
{ Now, is, the, time, for, all, good, men, to, come, to, the, aid, of, the, party}
};
...
{ // vector of vector of string
{ hello, world };// vector of string
{ The, quick, brown, fox, jumps, over, the, lazy, dog };
...
{ Now, is, the, time, for, all, good, men, to, come, to, the, aid, of, the, party}
};
}
那將如何很好地完成?
注意:按我的解釋,這不是問題的“真實”答案,因為我懷疑OP想要一個通用解決方案,該解決方案對任意嵌套的容器使用適當的縮進。
作為解決方法,您當然可以使用給定的解決方案,並適當地調整前綴,定界符和后綴。
范例 :
using namespace std::string_literals;
using vs = std::vector<std::string>;
using vvs = std::vector<std::vector<std::string>>;
using vvvs = std::vector<std::vector<std::vector<std::string>>>;
std::cout << pretty::decoration<vs>(" { ", ", ", " }");
std::cout << pretty::decoration<vvs>(" {\n", ",\n", "\n }");
std::cout << pretty::decoration<vvvs>("{\n", ",\n", "\n}\n");
std::vector<std::string> vs1 = { "hello"s, "world"s };
std::vector<std::string> vs2 = { "The"s, "quick"s, "brown"s, "fox"s };
std::vector<std::vector<std::string>> vvs1 = { vs1, vs1, vs2 };
std::vector<std::vector<std::string>> vvs2 = { vs2, vs1, vs2 };
std::vector<std::vector<std::vector<std::string>>> vvvs1 = { vvs1, vvs2 };
std::cout << vvvs1;
打印:
{
{
{ hello, world },
{ hello, world },
{ The, quick, brown, fox }
},
{
{ The, quick, brown, fox },
{ hello, world },
{ The, quick, brown, fox }
}
}
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