使用PHP將文件上傳到MySQL數據庫

Question

我有一個網頁，用戶可以用它上傳文件。 現在，該代碼可以成功地將文檔上傳到服務器上的目錄，而不會出現任何問題。 但是，我需要將文檔作為新插入的行上載到MySQL表，然后將文檔顯示為原始網頁上的鏈接。 但是，每次我嘗試上傳到MySQL時，它都會失敗，而且我不確定為什么會這樣。 在調試模式下收到0錯誤，並且可以登錄並成功連接到數據庫。 我的查詢失敗了，但是我可以在MySQL中成功運行查詢而不會出錯。

我的密碼：

HTML：

<body>

<br/>

<div id="bodydiv">

<fieldset id='title'>

  <span style='color:aliceblue'>Uploaded SG Documents</span>

</fieldset>

<br/>


<fieldset id='docTypeWO'>

  <span>Scanned Work Orders:</span>

  <div id='responseWO'>

  </div>

</fieldset>


<br/>


<fieldset id='docTypeCS'>

  <span>Cut Sheets:</span>

  <div id='responseCS'>

  </div>

</fieldset>


<br/>


<fieldset id='docTypeOther'>

  <span>Others:</span>

  <div id='responseOther'>

  </div>

</fieldset>


<br/>


<form name="sgFileUpload" id="sgFileUpload" action='sg_addupload.php' method="POST" enctype="multipart/form-data">




<fieldset id='uploadBtnField'>

  <input type="hidden" name="MAX_FILE_SIZE" value="50000000"/> 


  <input type='file' name='searchFile' id='searchFile' multiple>

  <input type='submit' name='startUpload' id='startUpload' value='Upload'>

  <!-- <input type='reset' name='cancelUpload' id='cancelUpload' value="Cancel Upload">

  <input type='button' name='deleteFile' id='deleteFile' value='Delete'> -->

</fieldset>

<!-- The table listing the files available for upload/download -->
    <table><tbody></tbody></table>



  </form> <!-- End Form Input -->

</div>

</body> 
</html>

我的AJAX：

                j('#startUpload').on('click', function() {
                    var file_data = j('#searchFile').prop('files')[0];   
                    var form_data = new FormData();                  
                    form_data.append('file', file_data);
                    alert(form_data);                             
                    j.ajax({
                            url: 'sg_addupload.php', // point to server-side PHP script 
                            dataType: 'text',  // what to expect back from the PHP script, if anything
                            cache: false,
                            contentType: false,
                            processData: false,
                            data: form_data,                         
                            type: 'POST',
                            success: function(data){
                                j('#responseWO').html(data); // display response from the PHP script, if any
                            }
                     });
                });

我的PHP：

include('inc.php');


//This section works successfully to upload to a directory on the server.

if ( 0 < $_FILES['file']['error'] ) {
    echo 'Error: ' . $_FILES['file']['error'] . '<br>';
}
else {
    move_uploaded_file($_FILES['file']['tmp_name'], 'uploads/' . $_FILES['file']['name']);
}





//This section fails...


    //This is the directory where images will be saved
    $target = "uploads/";
    $target = $target . basename( $_FILES['file']['name']);


    //This gets all the other information from the form
    $fileName = basename( $_FILES['file']['name']);
    $tmpName  = $_FILES['file']['tmp_name'];
    $fileSize = $_FILES['file']['size'];
    $fileType = $_FILES['file']['type'];

    $fp      = fopen($tmpName, 'r');
    $content = fread($fp, filesize($tmpName));
    $content = addslashes($content);
    fclose($fp);


    if(!get_magic_quotes_gpc())
    {
        $fileName = addslashes($fileName);
    }



    //Writes the Filename to the server
    if(move_uploaded_file($_FILES['file']['tmp_name'], $target)) {

        //Tells you if its all ok
        echo "The file ". basename( $_FILES['file']['name']). " has been uploaded, and your information has been added to the directory";


        //connect  to the database 
        $conn = new mysqli($servername, $username, $password, $dbname);

        // Check connection
        if(mysqli_connect_errno() ) {
            printf('Could not connect: ' . mysqli_connect_error());
            exit();
            }

        $conn->select_db($dbname);

        if(! $conn->select_db($dbname) ) {
            echo 'Could not select database. '.'<BR>';
        }


        //Writes the information to the database
        mysqli_query("INSERT INTO sg_uploads(sgref,file,type,size,content,doctype) VALUES('4','$fileName','$fileType','$fileSize','$content','Other')");
        } else {
            //Gives an error if its not
            echo "Sorry, there was a problem uploading your file.";
        }

感謝所有幫助。 謝謝！

Answer 1

<?php
error_reporting(E_ALL ^ E_DEPRECATED);
if(isset($_POST['btn-upload'])) {
include '../includes/dbcon.php';   

    $file = $_FILES['file']['name'];
    $file_loc = $_FILES['file']['tmp_name'];
    $file_size = $_FILES['file']['size'];
    $file_type = $_FILES['file']['type'];
    $title = mysqli_real_escape_string($con, $_POST['title']);
    $keywords = mysqli_real_escape_string($con, $_POST['keywords']);
    $categ = mysqli_real_escape_string($con, $_POST['categ']);
    $email = mysqli_real_escape_string($con, $_POST['email']);
    $art_info = mysqli_real_escape_string($con, $_POST['art_info']);
    $folder="../uploads_art_jou/";

$allowed =  array('pdf','doc' ,'docx');
    $file = $_FILES['file']['name'];
    $ext = pathinfo($file, PATHINFO_EXTENSION); 
$file = $folder."$file";    
    //$location =mysqli_real_escape_string ($con, $_POST['location']);

    // new file size in KB
    $new_size = $file_size/1024;  
    // new file size in KB

    // make file name in lower case
    $new_file_name = strtolower($file);

//checks file extension for images only

        if(!in_array($ext,$allowed) ) 
            { 
?>
<script>
       alert('file extension not allowed');
       window.location.href='art_jou_add.php?file_type_not_allowed_error';
</script>

<?php 
    }

//check whether file exist in said folder

        elseif (file_exists($file))
            { 
?>
<script>
       alert('file already exist');
       window.location.href='art_jou_add.php?file_exist';
</script>
<?php
    }

//if file does not exist, move it to folder and save details to table
    else(move_uploaded_file($file_loc,$folder.$file));
    {

    $sql="INSERT INTO art_jou(file,type,size,title,keywords,categ,email,art_info)
             VALUES('$file','$file_type','$file_size','$title','$keywords','$categ','$email','$art_info')";
    mysqli_query($con,$sql);
    echo "it is done";
?>

<?php
    }

    }

?>

這對我有用

使用PHP將文件上傳到MySQL數據庫

問題描述

1 個解決方案

解決方案1
2 2017-02-18 17:25:15

使用PHP將文件上傳到MySQL數據庫

問題描述

1 個解決方案

解決方案1 2 2017-02-18 17:25:15

解決方案1
2 2017-02-18 17:25:15