[英]Split a string with multiple delimiters into 3 parts
我從xml文件中讀取了一個字符串。 我需要將它分成3部分。 我需要在select語句中為插入查詢運行此查詢。 更新我想在insert語句的select查詢中使用它。
插入到table1(col1,col2,company,station,location,coln)select(這里我希望每個列都有這個查詢。)
字符串示例:
@declare exValue1 nvarchar(100) = 'Tempo > XNX (Marc) > Stores/Parts';
@declare exValue2 nvarchar(100) = 'Sedan 12 > XNX (Peter Inc) > Stores/Inventory';
@declare @company varchar(25);
@declare @station varchar(25);
@declare @location varchar(50);
分隔符是4個字符,它總是相同的。
例如第一個字符串,我需要拆分並分配
Tempo to company, XNX (Marc) to station, Stores/Parts to location.
例如第二個字符串
Sedan 12 to company, XNX (Peter Inc) to station, Stores/Inventory to location.
我嘗試使用charindex
substring
,但我只能獲得第一和第二個字符串,但我無法准確獲取位置字符串。 任何幫助贊賞TIA。
select @company = SUBSTRING(@exValue1, 1, CHARINDEX('>', @test) - 1)
select @station = SUBSTRING (@exValue1, CHARINDEX('>', @test) + 4, LEN(@test))
我無法正確計算位置和車站。
這將按順序為您提供字符串的三個部分
declare @exValue1 nvarchar(100) = 'Tempo > XNX (Marc) > Stores/Parts';
SELECT LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))) AS slices
FROM (SELECT CAST('<XMLRoot><RowData>' + REPLACE(@exValue1,'>','</RowData><RowData>') + '</RowData></XMLRoot>' AS XML) AS x)t
CROSS APPLY x.nodes('/XMLRoot/RowData')m(n)
但如果你想做變量,那么你去..
declare @exValue1 nvarchar(100) = 'Tempo > XNX (Marc) > Stores/Parts';
select SUBSTRING(@exValue1, 1, CHARINDEX('>', @exValue1) - 1)
set @exValue1 = SUBSTRING(@exValue1,CHARINDEX('>', @exValue1)+4,len(@exValue1))
select SUBSTRING(@exValue1, 1, CHARINDEX('>', @exValue1) - 1)
set @exValue1 = SUBSTRING(@exValue1,CHARINDEX('>', @exValue1)+4,len(@exValue1))
select @exValue1
創建一次函數並使用它一百萬次:)
CREATE FUNCTION dbo.splitstring ( @stringToSplit VARCHAR(MAX) )
RETURNS
@returnList TABLE ([Name] [nvarchar] (500))
AS
BEGIN
DECLARE @name NVARCHAR(255)
DECLARE @pos INT
WHILE CHARINDEX('>', @stringToSplit) > 0
BEGIN
SELECT @pos = CHARINDEX('>', @stringToSplit)
SELECT @name = SUBSTRING(@stringToSplit, 1, @pos-1)
INSERT INTO @returnList
SELECT @name
SELECT @stringToSplit = SUBSTRING(@stringToSplit, @pos+4, LEN(@stringToSplit)-@pos)
END
INSERT INTO @returnList
SELECT @stringToSplit
RETURN
END
使用以下功能:
declare @exValue1 nvarchar(100) = 'Tempo > XNX (Marc) > Stores/Parts';
declare @company varchar(25)
set @company=(select top 1 name from dbo.splitstring(@exValue1))
declare @station varchar(25)
set @station=(select top 1 name from dbo.splitstring(@exValue1) where name not in (select top 1 name from dbo.splitstring(@exValue1)))
declare @location varchar(50)
set @location=(select top 1 name from dbo.splitstring(@exValue1) where name not in (select top 2 name from dbo.splitstring(@exValue1)))
print @company+' to comapny, '+@station+' to station, '+@location+' to location. '
試試這個吧。 這會將字符串轉換為動態字符串並給出值
declare @exValue1 nvarchar(100) = 'Tempo > XNX (Marc) > Stores/Parts';
declare @exValue2 nvarchar(100) = 'Sedan 12 > XNX (Peter Inc) > Stores/Inventory';
declare @company varchar(25);
declare @station varchar(25);
declare @location varchar(50);
DECLARE @Tbl AS TABLE(company varchar(25), station varchar(25), location varchar(50))
SET @exValue1 = 'SELECT '''+REPLACE(@exValue1,'>',''' , ''')+''''
INSERT INTO @Tbl
EXEC(@exValue1)
SET @exValue2 = 'SELECT '''+REPLACE(@exValue2,'>',''' , ''')+''''
INSERT INTO @Tbl
EXEC(@exValue2)
SELECT * FROM @Tbl
您可以嘗試使用REVERSE()
來獲取如下所示的Location
declare @exValue1 nvarchar(100) = 'Tempo > XNX (Marc) > Stores/Parts';
declare @exValue2 nvarchar(100) = 'Sedan 12 > XNX (Peter Inc) > Stores/Inventory';
declare @company varchar(25);
declare @station varchar(25);
declare @location varchar(50);
select @company= SUBSTRING(@exValue1,1,CHARINDEX('>',@exValue1)-1)
select @location = reverse(SUBSTRING(reverse(@exValue1),1, CHARINDEX(';tg&',reverse(@exValue1))-1))
select @station = REPLACE(REPLACE(REPLACE(@exValue1,@company,''),@location,''),'>','')
select @company company, @station station, @location location;
這給了我以下結果
declare @exValue1 nvarchar(100) = 'Tempo > XNX (Marc) > Stores/Parts'
,@company varchar(25)
,@station varchar(25)
,@location varchar(50)
select @company = x.value('(/r/e)[1]','nvarchar(25)')
,@station = x.value('(/r/e)[2]','nvarchar(25)')
,@location = x.value('(/r/e)[3]','nvarchar(50)')
from (select cast ('<r><e>'+replace(@exValue1,'>','</e><e>')+'</e></r>' as xml) as x) x
select @company,@station,@location
+-------+------------+--------------+
| Tempo | XNX (Marc) | Stores/Parts |
+-------+------------+--------------+
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