選擇隨機數組，然后從該數組中選擇一個元素

Question

我試圖弄清楚是否有可能首先選擇一個隨機數組（在加載時），然后從這個選擇的數組中選擇一個元素。 例如，我有：

    var colorsOne = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsTwo = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsThree = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsFour = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsFive = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsSix = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsSeven = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsEight = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsNine = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsTen = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsEleven = ["#CCCCCC","#333333","#990099","#990099"];  
    var colorsTwelve = ["#CCCCCC","#333333","#990099","#990099"];  

12個數組（每個數組最終將填充不同的十六進制代碼），我首先需要從這些數組中選擇一個，然后從該數組中選擇一個十六進制代碼（隨機）。

例如

var rand = Math.floor(Math.random() * 4);               
$('.header-wrap').css("background-color", colorsEight[rand]);

這將從coloursEight數組中獲取一個隨機元素，但是我不得不對此進行編程，我需要首先隨機選擇一個數組，然后從該數組中選擇一個元素。

任何建議，將不勝感激！

Answer 1

答案幾乎是問題固有的。 :-)將數組放入數組，然后做同樣的事情：

var colors = [
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"],
    ["#CCCCCC","#333333","#990099","#990099"]
];

var array = colors[Math.floor(Math.random() * colors.length)];
var color = array[Math.floor(Math.random() * array.length)];
$('.header-wrap').css("background-color", color);

如果由於某些原因需要這些單獨的數組變量，則仍可以將它們收集在一起：

var colorsOne = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsTwo = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsThree = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsFour = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsFive = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsSix = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsSeven = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsEight = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsNine = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsTen = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsEleven = ["#CCCCCC","#333333","#990099","#990099"];  
var colorsTwelve = ["#CCCCCC","#333333","#990099","#990099"]
var colors = [
    colorsOne,
    colorsTwo,
    colorsThree,
    colorsFour,
    colorsFive,
    colorsSix,
    colorsSeven,
    colorsEight,
    colorsNine,
    colorsTen,
    colorsEleven,
    colorsTwelve
];

var array = colors[Math.floor(Math.random() * colors.length)];
var color = array[Math.floor(Math.random() * array.length)];
$('.header-wrap').css("background-color", color);

Answer 2

您只需要從所有現有數組生成二維數組。

var super_array = [colorsOne, colorsTwo, ...];

然后，只需獲取super_array的隨機索引，您便有了一個可以滿足您內心需求的數組。

var rand_x = Math.floor(Math.random() * 4); 
var rand_y = Math.floor(Math.random() * 4);              
$('.header-wrap').css("background-color", super_array[rand_x][rand_y]);

Answer 3

function randomArrVal(arr) {
 return arr[Math.floor(arr.length * Math.random())];
}
var array2D = [
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"],
  ["#CCCCCC","#333333","#990099","#990099"]
];

$('.header-wrap').css("background-color", randomArrVal(randomArrVal(array2D)));

Answer 4

似乎沒有理由創建命名數組。 您可以只創建一個多維數組，然后從中獲得所需的顏色。 下面的代碼片段演示了這一點。

    // BUNDLE ALL THE INDIVIDUAL ARRAY OF COLORS
    // INTO ONE SINGLE ARRAY THUS CREATING A MULTI-DIMENSIONAL ARRAY.
    var arrHexColors    = [
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"],
        ["#CCCCCC","#333333","#990099","#990099"]
    ];

    // IF NECESSARY (SHOULD THE KEYS BE IMPORTANT TO YOU);
    // CREATE AN ARRAY TO HOLD THE KEYS TO THE INDIVIDUAL ARRAY...
    // THE IDEA HERE IS TO CREATE A PARALLEL ARRAY, WITH THE KEYS HERE
    // CORRESPONDING TO THE KEYS REPRESENTING ITS CONTENT IN THE MULTI-DIMENSIONAL ARRAY.
    var arrColorKeys    = [
        'colorsOne',
        'colorsTwo',
        'colorsThree',
        'colorsFour',
        'colorsFive',
        'colorsSix',
        'colorsSeven',
        'colorsEight',
        'colorsNine',
        'colorsTen',
        'colorsEleven',
        'colorsTwelve'
    ];

    // GENERATE A RANDOM NUMBER THAT SHOULD BE 
    // "ONE" LESS THAN THE LENGTH OF THE MULTI-DIMENSIONAL ARRAY
    var arrRandomColor  = arrHexColors[ Math.floor(Math.random() * arrHexColors.length) ];

    // DO THE SAME FOR THE COLOR KEYS ARRAY - IF NEEDED....
    var arrRandomKey    = arrRandomColor[ Math.floor(Math.random() * arrRandomColor.length) ];

    // USING THE GENERATED RANDOM NUMBER PICK THE ARRAY 
    // CORRESPONDING TO THAT KEY
    var randomColor     = arrRandomColor[ Math.floor(Math.random() * arrRandomColor.length) ];

    $('.header-wrap').css("background-color", randomColor);

    console.log(randomColor);