MySQL＃1052如何解決？

Question

如何解決呢？ （我認為它是最后加入）

SELECT id, prumer
FROM 
SELECT id, AVG( s ) prumer
FROM hodnoceni
GROUP BY id
)p
JOIN (
SELECT MIN( prumer ) nejhorsi, MAX( prumer ) nejlepsi
FROM (
SELECT id, AVG( s ) prumer
FROM hodnoceni
GROUP BY id
)p
)q ON p.prumer = q.nejhorsi
OR p.prumer = q.nejlepsi
JOIN op_add r ON p.id = r.id

JOIN op_add r ON p.id = r.id

請幫我 ！ :)

Answer 1

雖然不是很清楚，但是您的查詢在語法上是錯誤的。 應該是這樣的

SELECT id, prumer
FROM (
SELECT id, AVG(s) as prumer
FROM hodnoceni
GROUP BY id
) p
JOIN (
SELECT MIN( prumer ) nejhorsi, MAX( prumer ) nejlepsi
FROM hodnoceni
GROUP BY id
)q ON p.prumer = q.nejhorsi OR p.prumer = q.nejlepsi
JOIN op_add r ON p.id = r.id;

好吧，您發布的查詢很奇怪，並且沒有足夠的信息說明您要查找的內容，因此建議的解決方案僅用於語法不匹配 。 您的查詢應該像

SELECT p.id, p.prumer
FROM (
SELECT id, AVG(s) as prumer
FROM hodnoceni
GROUP BY id
) p
JOIN (
SELECT MIN(prumer) as nejhorsi, MAX(prumer) as nejlepsi
FROM (
SELECT id, AVG(s) as prumer
FROM hodnoceni
GROUP BY id
)pp
)q ON p.prumer = q.nejhorsi OR p.prumer = q.nejlepsi
JOIN op_add r ON p.id = r.id;