[英]how to select * from table where col1+col2=b using active record
如何運行select * from table where col1+col2=b;
使用codeigniter的活動記錄。 使用mysql
我嘗試了這個但是失敗了
$this->db->where("col1 + col2",$b)->get("table")->result_array();
您的SQL語法有誤; 檢查與您的MariaDB服務器版本相對應的手冊以獲取在第4行的'915087'附近使用的正確語法
選擇*從
table
a + b 25
$this->db->select('(col1+col2) as col3');
$this->db->from('table');
$this->db->HAVING('col3 = ', $b);
$query = $this->db->get();
嘗試這個。
您可以按照自己的想法去做。 只需按照以下代碼解決您的錯誤即可。 謝謝。 如果有用,請確認。
$b = 25;
$data = $this->db->where(array("(number1 + number2) = " => $b))->get("dummy_table")->result_array();
echo "<pre>";
print_r($data);
// output
Array
(
[0] => Array
(
[id] => 1
[number1] => 10
[number2] => 15
[number3] => 25
)
[1] => Array
(
[id] => 2
[number1] => 23
[number2] => 2
[number3] => 25
)
[2] => Array
(
[id] => 3
[number1] => 9
[number2] => 16
[number3] => 25
)
[3] => Array
(
[id] => 4
[number1] => 23
[number2] => 2
[number3] => 25
)
)
$this->load->model('dummy_table_model');
$b = 25;
$data = $this->db->get_where("dummy_table", array("(number1 + number2) = " => $b))->result_array();
// $this->db->last_query();
var_dump($data);
// Out put
array (size=4)
0 =>
array (size=4)
'id' => string '1' (length=1)
'number1' => string '10' (length=2)
'number2' => string '15' (length=2)
'number3' => string '25' (length=2)
1 =>
array (size=4)
'id' => string '2' (length=1)
'number1' => string '23' (length=2)
'number2' => string '2' (length=1)
'number3' => string '25' (length=2)
2 =>
array (size=4)
'id' => string '3' (length=1)
'number1' => string '9' (length=1)
'number2' => string '16' (length=2)
'number3' => string '25' (length=2)
3 =>
array (size=4)
'id' => string '4' (length=1)
'number1' => string '23' (length=2)
'number2' => string '2' (length=1)
'number3' => string '25' (length=2)
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