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[英]Unexpected token (END_OBJECT), expected FIELD_NAME: missing property '@type' that is to contain type id
[英]Jackson serialization and nexpected token (END_OBJECT), expected FIELD_NAME: missing property 'name'
我正在嘗試編寫使用Jackson序列化/反序列化對象的代碼。
這些對象本質上是多態的:
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "name")
@JsonSubTypes({
@Type(value = ComparableQuery.class),
@Type(value = CompositeQuery.class)
})
public abstract class BaseQuery {
private final Long characteristicId;
...
}
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "name")
public class CompositeQuery extends BaseQuery {
private final String operator;
private final BaseQuery[] queries;
public CompositeQuery(Long characteristicId, Operator operator, BaseQuery... queries) {
super(characteristicId);
this.operator = operator.value;
this.queries = queries;
}
...
}
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "name")
@JsonSubTypes({
@Type(value = EqualQuery.class),
@Type(value = GreaterOrEqualQuery.class),
@Type(value = GreaterQuery.class),
@Type(value = LessOrEqualQuery.class),
@Type(value = LessQuery.class)
})
public abstract class ComparableQuery extends BaseQuery {
private final Object value;
private final String comparisonOperator;
...
}
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "name")
public class EqualQuery extends ComparableQuery {
public EqualQuery(Long characteristicId, Object value) {
super(characteristicId, value, "=");
}
}
我用以下代碼創建了Set<BaseQuery>
:
Set<BaseQuery> queries = new HashSet<>();
BaseQuery megapixelCharacteristicQuery = new CompositeQuery(megapixelCharacteristic.getCharacteristicId(), CompositeQuery.Operator.AND, new GreaterOrEqualQuery(megapixelCharacteristic.getCharacteristicId(), 10), new LessOrEqualQuery(megapixelCharacteristic.getCharacteristicId(), 50));
queries.add(megapixelCharacteristicQuery);
現在,當我嘗試序列化對象時,會收到以下JSON:
[
{
"characteristicId":391,
"operator":"AND",
"queries":[
{
"name":"GreaterOrEqualQuery",
"characteristicId":391,
"value":10,
"comparisonOperator":">="
},
{
"name":"LessOrEqualQuery",
"characteristicId":391,
"value":50,
"comparisonOperator":"<="
}
]
}
]
但是當我嘗試反序列化JSON文檔時,我收到以下異常:
com.fasterxml.jackson.databind.JsonMappingException: Unexpected token (END_OBJECT), expected FIELD_NAME: missing property 'name' that is to contain type id (for class com.example.decision.query.characteristic.BaseQuery)
at [Source: [{"characteristicId":391,"operator":"AND","queries":[{"name":"GreaterOrEqualQuery","characteristicId":391,"value":10,"comparisonOperator":">="},{"name":"LessOrEqualQuery","characteristicId":391,"value":50,"comparisonOperator":"<="}]}]; line: 1, column: 233] (through reference chain: java.util.HashSet[0])
at com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:261)
由於某種原因,JSON根對象中沒有name
字段。
如何解決?
更新
當我嘗試僅序列化例如megapixelCharacteristicQuery
對象時,它工作正常:
BaseQuery megapixelCharacteristicQuery = new CompositeQuery(megapixelCharacteristic.getCharacteristicId(), CompositeQuery.Operator.AND, new GreaterOrEqualQuery(megapixelCharacteristic.getCharacteristicId(), 10), new LessOrEqualQuery(megapixelCharacteristic.getCharacteristicId(), 50));
在這種情況下,Jackson形成以下JSON(帶有正確的"name":"CompositeQuery"
):
{
"name":"CompositeQuery",
"characteristicId":391,
"operator":"AND",
"queries":[
{
"name":"GreaterOrEqualQuery",
"characteristicId":391,
"value":10,
"operator":">="
},
{
"name":"LessOrEqualQuery",
"characteristicId":391,
"value":50,
"operator":"<="
}
]
}
但是將megapixelCharacteristicQuery
放在HashSet<BaseQuery>
內時,序列化/反序列化仍然不起作用。
如何使其與HashSet一起使用?
另外,當我向JsonTypeInfo
批注中添加defaultImpl = CompositeQuery.class
時,即使使用HashSet
,它也可以開始正常工作,例如:
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "name", defaultImpl = CompositeQuery.class)
@JsonSubTypes({
@Type(value = ComparableQuery.class),
@Type(value = CompositeQuery.class)
})
public abstract class BaseQuery {
...
}
但這不是我的選擇,因為我不知道在不同情況下應使用哪種類型,因此我仍在尋找一種解決方案,該方法如何在JSON中正確提供name
參數。
最后,感謝以下問題中提供的答案, 為什么傑克遜多態序列化在列表中不起作用? 我找到了解決方案:
Set<BaseQuery> queries = new HashSet<BaseQuery>() {
};
做到了。 現在一切都按預期進行。
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