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從 HTML Canvas 獲取像素?

[英]Get a pixel from HTML Canvas?

是否可以查詢 HTML Canvas object 以獲取特定位置的顏色?

W3C 文檔中有一個關於 像素操作的部分。

這是一個關於如何反轉圖像的示例

var context = document.getElementById('myCanvas').getContext('2d');

// Get the CanvasPixelArray from the given coordinates and dimensions.
var imgd = context.getImageData(x, y, width, height);
var pix = imgd.data;

// Loop over each pixel and invert the color.
for (var i = 0, n = pix.length; i < n; i += 4) {
    pix[i  ] = 255 - pix[i  ]; // red
    pix[i+1] = 255 - pix[i+1]; // green
    pix[i+2] = 255 - pix[i+2]; // blue
    // i+3 is alpha (the fourth element)
}

// Draw the ImageData at the given (x,y) coordinates.
context.putImageData(imgd, x, y);

嘗試 getImageData 方法:

var data = context.getImageData(x, y, 1, 1).data;
var rgb = [ data[0], data[1], data[2] ];

是的,只要你有它的上下文。 (查看如何在此處獲取 canvas 上下文。)

var imgData = context.getImageData(0,0,canvas.width,canvas.height)
// { data: [r,g,b,a,r,g,b,a,r,g,..], ... }

function getPixel(imgData, index) {
  var i = index*4, d = imgData.data
  return [d[i],d[i+1],d[i+2],d[i+3]] // Returns array [R,G,B,A]
}

// AND/OR

function getPixelXY(imgData, x, y) {
  return getPixel(imgData, y*imgData.width+x)
}



PS:如果你打算在 canvas 上對數據進行變異並將它們拉回,你可以使用subarray

var
  idt = imgData, // See previous code snippet
  a = getPixel(idt, 188411), // Array(4) [0, 251, 0, 255]
  b = idt.data.subarray(188411*4, 188411*4 + 4) // Uint8ClampedArray(4) [0, 251, 0, 255]

a[0] = 255 // Does nothing
getPixel(idt, 188411) // Array(4) [0, 251, 0, 255]

b[0] = 255 // Mutates the original imgData.data
getPixel(idt, 188411) // Array(4) [255, 251, 0, 255]

// Or use it in the function
function getPixel(imgData, index) {
  var i = index*4, d = imgData.data
  return imgData.data.subarray(i, i+4) // Returns subarray [R,G,B,A]
}

您可以在http://qry.me/xyscope/上進行實驗,此代碼在源代碼中,只需在控制台中復制/粘貼即可。

function GetPixel(context, x, y)
{
    var p = context.getImageData(x, y, 1, 1).data; 
    var hex = "#" + ("000000" + rgbToHex(p[0], p[1], p[2])).slice(-6);  
    return hex;
}

function rgbToHex(r, g, b) {
    if (r > 255 || g > 255 || b > 255)
        throw "Invalid color component";
    return ((r << 16) | (g << 8) | b).toString(16);
}

是的,看看 getImageData()。 下面是使用 canvas 破解 JavaScript 驗證碼的示例:

JavaScript 中的 OCR 和神經網絡

請注意,getImageData 返回一個快照。 含義是:

  • 直到后續的 putImageData 更改才會生效
  • getImageData 和 putImageData 調用相對較慢
// Get pixel data
var imageData = context.getImageData(x, y, width, height);

// Color at (x,y) position
var color = [];
color['red'] = imageData.data[((y*(imageData.width*4)) + (x*4)) + 0];
color['green'] = imageData.data[((y*(imageData.width*4)) + (x*4)) + 1];
color['blue'] = imageData.data[((y*(imageData.width*4)) + (x*4)) + 2];
color['alpha'] = imageData.data[((y*(imageData.width*4)) + (x*4)) + 3];

您可以使用i << 2

const data = context.getImageData(x, y, width, height).data;
const pixels = [];

for (let i = 0, dx = 0; dx < data.length; i++, dx = i << 2) {
    pixels.push({
        r: data[dx  ],
        g: data[dx+1],
        b: data[dx+2],
        a: data[dx+3]
    });
}

如果您想通過將像素坐標傳遞給 function 來提取特定顏色的像素,這將派上用場:

var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
function detectColor(x, y){
  data=ctx.getImageData(x, y, 1, 1).data;
  col={
    r:data[0],
    g:data[1],
    b:data[2]
  };
  return col;
}

x , y是要過濾掉顏色的坐標。

var color = detectColor(x, y)

顏色為 object,您將通過color.r , color.g , color.b獲得 RGB 值。

快速方便

使用以下 class 實現本文中描述的快速方法並包含您需要的所有內容: readPixelputPixel , get width/height Class 在調用refresh()方法后更新 canvas。 示例求解二維波動方程的簡單情況

 class Screen{ constructor(canvasSelector) { this.canvas = document.querySelector(canvasSelector); this.width = this.canvas.width; this.height = this.canvas.height; this.ctx = this.canvas.getContext('2d'); this.imageData = this.ctx.getImageData(0, 0, this.width, this.height); this.buf = new ArrayBuffer(this.imageData.data.length); this.buf8 = new Uint8ClampedArray(this.buf); this.data = new Uint32Array(this.buf); } // r,g,b,a - red, gren, blue, alpha components in range 0-255 putPixel(x,y,r,g,b,a=255) { this.data[y * this.width + x] = (a << 24) | (b << 16) | (g << 8) | r; } readPixel(x,y) { let p= this.data[y * this.width + x] return [p&0xff, p>>8&0xff, p>>16&0xff, p>>>24]; } refresh() { this.imageData.data.set(this.buf8); this.ctx.putImageData(this.imageData, 0, 0); } } // -------- // TEST // -------- let s=new Screen('#canvas'); function draw() { for (var y = 1; y < s.height-1; ++y) { for (var x = 1; x < s.width-1; ++x) { let a = [[1,0],[-1,0],[0,1],[0,-1]].reduce((a,[xp,yp])=> a+= s.readPixel(x+xp,y+yp)[0],0); let v=a/2-tmp[x][y]; tmp[x][y]=v<0? 0:v; } } for (var y = 1; y < s.height-1; ++y) { for (var x = 1; x < s.width-1; ++x) { let v=tmp[x][y]; tmp[x][y]= s.readPixel(x,y)[0]; s.putPixel(x,y, v,v,v); } } s.refresh(); window.requestAnimationFrame(draw) } // temporary 2d buffer ()for solving wave equation) let tmp = [...Array(s.width)].map(x => Array(s.height).fill(0)); function move(e) { s.putPixel(ex-10, ey-10, 255,255,255);} draw();
 <canvas id="canvas" height="150" width="512" onmousemove="move(event)"></canvas> <div>Move mouse on black box</div>

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