[英]Serialization of an object type enum contained in a serializable class
我試圖序列化在我的可序列化類中聲明的對象類型枚舉。 我已經在這里更新了所有主題,但我沒有找到我的問題的答案。 我希望有人可以幫助我。 我實際上是在嘗試序列化2個對象類型SType和CbitSet,但我得到以下結果:
<rSIt>
<sType>S_V_INC</sType>
<bits/>
<mHave>true</mHave>
</rSIt>
我期待的是:
<rSIt>
<sType>
<code>VI</code>
<description>V Inc</description>
<name>S_V_INC</name>
</sType>
<bits>
<words>{long[7]@5285}</words>
<wordsInUse>7</wordsInUse>
<sizeIsSticky>false</sizeIsSticky>
<bits>
<mHave>true</mHave>
</rSIt>
這是我的代碼:
@XmlRootElement(name="rSIt")
@XmlAccessorType(XmlAccessType.FIELD)
public class RSIt implements Serializable{
private static final long serialVersionUID = -5848959699974019999L;
@XmlElement
private SType sType;
@XmlElement
private CbitSet bits = new CbitSet();
@XmlElement
private boolean mHave = true;
public SType getSType() {
return this.sType;
}
public void setSType(SType sType) {
this.sType = sType;
}
public CbitSet getBits() {
return this.bits;
}
public boolean ismHave() {
return this.mHave;
}
public void setmHave(boolean mHave) {
this.mHave = mHave;
}
public RSIt() {
super();
}
public RSIt(SType sType, boolean mHave) {
super();
this.sType = sType;
this.mHave = mHave;
}
public RSIt(SType sType, boolean mHave, Integer bit) {
super();
this.sType = sType;
this.mHave = mHave;
this.bits.set(bit);
}
}
This is the implementation of SType class (it is an Enum class):
public enum SType {
S_V_INC ("VI", "V Inc"),
S_V_EXC ("VE", "V Exc"),
S_RP_INC ("RI", "RP Inc"),
S_RP_EXC ("RE", "RP Exc"),
S_V_AN_F ("VA", "V F All");
private final String code;
private final String description;
SearchType (String code, String description) {
this.code = code;
this.description = description;
}
public String getCode() {
return code;
}
public String getDescription() {
return description;
}
}
This is the implementation of CbitSet class
import java.util.BitSet;
@XmlRootElement(name="rSIt")
@XmlAccessorType(XmlAccessType.FIELD)
public class CbitSet extends BitSet implements Serializable{
private static final long serialVersionUID = 476550000000055127L;
private static final long longOne = 1;
private static final long long64 = 64;
public CbitSet() {
super();
}
public long[] toLongArray() {
long[] longs = new long[this.size() / 64];
for (int i = 0; i < longs.length; i++)
for (int j = 0; j < 64; j++)
if (this.get(i * 64 + j))
longs[i] |= longOne << j;
return longs;
}
public void fromLongArray(long[] longs) {
for (int i=0; i<longs.length*64; i++) {
if ((longs[i/64]&(longOne<<(i%long64))) != 0) {
this.set(i);
}
}
}
public String toBitString() {
StringBuilder sb = new StringBuilder();
for (int x = 0; x < this.size(); x++) {
if (this.get(x)) {
sb.append("1");
} else {
sb.append("0");
}
}
return sb.toString();
}
public void fromBitString(String string) {
int pos = 0;
for (byte chr : string.getBytes()) {
if ('1' == chr) {
this.set(pos);
}
pos++;
}
}
public void set(List<Integer> bits) {
set(bits,true);
}
public void set(List<Integer> bits, boolean value) {
if (bits != null) {
for (Integer bit : bits) {
if (bit != null) {
this.set(bit.intValue(), value);
}
}
}
}
public void set(Integer bitIndex) {
if (bitIndex != null) {
super.set(bitIndex);
}
}
public void set(Integer bitIndex, boolean value) {
if (bitIndex != null) {
super.set(bitIndex, value);
}
}
}
Thank you for your help guys.
我也在學習......我傾向於同意另一個SO問題的答案( 這里 )
Java中的
Enum
是不可變對象,在這種情況下,序列化其任何字段都沒有意義。
但是,如果因任何原因,你堅持按照您的指定來獲取編組的結果,我發現我能做到這一點,通過改變SType
從enum
的類,然后嵌入另一個enum
稱為EnumSType
在里面。
代碼如下所示:
package SerializationQuestion1;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlTransient;
@XmlRootElement(name="sType")
@XmlAccessorType(XmlAccessType.FIELD)
public class SType {
public enum EnumSType {
S_V_INC ("VI", "V Inc"),
S_V_EXC ("VE", "V Exc"),
S_RP_INC ("RI", "RP Inc"),
S_RP_EXC ("RE", "RP Exc"),
S_V_AN_F ("VA", "V F All");
@XmlElement
private final String code;
@XmlElement
private final String description;
EnumSType (String code, String description) { // Bug fix 1
this.code = code;
this.description = description;
}
public String getCode() {
return code;
}
public String getDescription() {
return description;
}
}
@XmlTransient
private EnumSType sType;
public EnumSType getsType() {
return sType;
}
public void setsType(EnumSType sType) {
this.sType = sType;
}
public SType () {};
public SType (EnumSType sType) {
this.sType = sType;
}
@XmlElement
public String getCode() { return this.sType.getCode();};
@XmlElement
public String getDescription() { return this.sType.getDescription();};
@XmlElement
public String getName() { return this.sType.name();};
}
要實例化RSIt
對象,代碼現在看起來像這樣:
RSIt rsit = new RSIt(new SType(EnumSType.S_V_INC), true, null);
以下是我的編組輸出:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<rSIt>
<sType>
<code>VI</code>
<description>V Inc</description>
<name>S_V_INC</name>
</sType>
<bits/>
<mHave>true</mHave>
</rSIt>
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