從PHP中的字符串中刪除單詞

Question

我正在嘗試從給定的輸入字符串中刪除一些特定的單詞，這些輸入單詞會分成多個單詞。 但是從拆分的單詞數組中，特定單詞不會被替換。

$string = $this->input->post('keyword');  
echo $string; //what i want is you

$string = explode(" ", $string);  

$string = array_values(array_filter(preg_replace('/[^A-Za-z0-9\']/','', $string)));  

$omit_words = array(' the ',' i ',' we ',' you ',' what ',' is ');  

$keyword = array_values(array_filter(str_ireplace($omit_words,'',$string)));  
print_r($keyword); // Array ([0] => what [1] => i [2] => want [3] => is [4] => you)  

預期產量：

Array ([0] => want)

我無法找出這是怎么回事。 請幫我解決這個問題。

Answer 1

首先從數組$omit_words的字符串中刪除空格。 $omit_words使用array_diff ：如果要重新索引輸出，可以使用array_values 。

$string='what i want is you'; //what i want is you

$string = explode(" ", $string);  

$omit_words = array('the','i','we','you','what','is');  
$result=array_diff($string,$omit_words);

print_r($result); // 

Answer 2

您可以使用array_diff ，然后使用array_values來重置數組索引。

<?php
$string = $this->input->post('keyword');
$string = explode(" ", $string);  

$omit_words = array('the','i','we','you','what','is');  
$result = array_values(array_diff($string,$omit_words));

print_r($result);  //Array ([0] => want)
?>

Answer 3

您將必須從omit_words中刪除空格：

$string = "what i want is you";

$string = explode(" ", $string);  

$string = array_values(array_filter(preg_replace('/[^A-Za-z0-9\']/','', $string)));

$omit_words = array('the','is','we','you','what','i');  

$keyword = array_values(array_filter(str_ireplace($omit_words, '', $string)));
print_r($keyword); // Array ( [0] => want ) 

Answer 4

嘗試這個

<?php
$string="what i want is you";
$omit_words = array('the','we','you','what','is','i');   // remove the spaces
rsort($omit_words); // need to sort so that correct words are replaced 
$new_string=str_replace($omit_words,'',$string);

print_r($new_string);