MySQL按一個表的兩列排序

Question

我有這張桌子：

CREATE TABLE table_name (id INT, for_id INT, comms VARCHAR(50));
    INSERT INTO table_name VALUES (1,0, 'boo'),
                                    (2,1, 'John'),
                                    (3,0, 'Zoe'),
                                    (4,3, 'bar'),
                                    (5,1, 'Don'),
                                    (6,3, 'FOO'),
                                    (7,1, 'Doe');

http://sqlfiddle.com/#!9/859933/6

我如何下一步：

1.0.'boo'
2.1.'John'
5.1.'Don'
7.1.'Doe'
3.0.'Zoe'
4.3.'bar'
6.3.'FOO'

謝謝！

Answer 1

不確定這是否是您真正想要的，您應該對發布后的結果順序進行一些說明。

select *
from table_name
order by 
    case when for_id = 0 then concat(id, for_id) + 0
         else concat(for_id, id) + 0
    end

和SQLFiddle演示在這里 。

更新：

再試一次，

select *
from table_name
order by 
    case when for_id = 0 then mod(concat(for_id, id) + 0, 10)
         else mod(concat(id, for_id) + 0, 10)
    end
    , id asc

SQLFiddle

再次更新：

select *
from table_name
order by 
    case when for_id = 0 then id
         else for_id
    end
    , id asc

SQLFiddle

Answer 2

只需使用order by ，它可以得到多個列

Select * from table_name 
  order by id asc, for_id asc;

Answer 3

使用訂購者和Cancat

select Concat(id,'.',for_id) as id ,comms
from table_name
order by id asc,for_id asc

更新 ：

根據您的條件使用命令並應用case聲明

select *
from table_name
order by 
    case when for_id = 0 then concat(id, for_id) + 1
         else concat(for_id, id) + 0
    end

http://sqlfiddle.com/#!9/859933/25