Doctrine查詢構建器提供錯誤的結果

Question

我有兩個實體Person和Nursery，我和JoinTable之間有一個ManyToMany關系。 我想做這2個SQL查詢：

1）使用nursery_id查找鏈接到托兒所的所有員工（= Person）

select p.* from person p inner join nursery_staff ns on p.id = ns.staff_id inner join nursery n on ns.nursery_id = n.id where n.id=1 and p.nursery_staff_role <> 'MANAGER';

2）找到staff_id的員工，並確保他與nursery_id鏈接到托兒所

select p.* from person p inner join nursery_staff ns on p.id = ns.staff_id inner join nursery n on ns.nursery_id = n.id where n.id=2 and p.id=4 and p.nursery_staff_role <> 'MANAGER';

為此我在PersonRepository中有這2個查詢：

1）

public function findAllStaffLinkedToANursery($nursery_id)
{
    $qb = $this->_em->createQueryBuilder();
    $qb->select('p')
        ->from($this->_entityName, 'p')
        ->innerJoin('VSCrmBundle:Nursery', 'n')
        ->where('n.id = :id')
        ->andWhere('p.nurseryRole <> :profession')
        ->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));

    return $qb->getQuery()->getResult();
}

2）

public function findOneByNurseryAndStaffId($nursery_id, $staff_id)
{
    $qb = $this->_em->createQueryBuilder();
    $qb->select('p')
        ->from($this->_entityName, 'p')
        ->innerJoin('VSCrmBundle:Nursery', 'n')
        ->where('p.id = :pid')
        ->andWhere('n.id = :nid')
        ->andWhere('p.nurseryRole <> :staffRole')
        ->setParameters(array(
            'pid' => $staff_id,
            'nid' => $nursery_id,
            'staffRole' => 'MANAGER'
        ));

    return $qb->getQuery()->getOneOrNullResult();
}

但是在這兩種情況下，查詢都不關心nursery_id，這使得我的工作人員不再使用nursery_id。 例如，id = 4的Person未與id = 2的托兒所鏈接，但此查詢顯示此人。

編輯：我有與dql查詢相同的結果：

 php bin/console doctrine:query:dql "select p.email from VSCrmBundle:Person p inner join VSCrmBundle:Nursery n where n.id=2 and p.nurseryRole <> 'MANAGER'"

Answer 1

也許這就是你加入幼兒園實體的方式。 嘗試從Person實體屬性加入它，如下所示：

public function findAllStaffLinkedToANursery($nursery_id)
{
    $qb = $this->_em->createQueryBuilder();
    $qb->select('p')
        ->from($this->_entityName, 'p')
        ->innerJoin('p.nursery', 'n')
        ->where('n.id = :id')
        ->andWhere('p.nurseryRole <> :profession')
        ->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));

    return $qb->getQuery()->getResult();
}

這當然只有在Person具有屬性托兒所並且使用Doctrine ORM映射時才有效。 如果存儲庫擴展了Doctrine \\ ORM \\ EntityRepository，您還可以簡化它：

public function findAllStaffLinkedToANursery($nursery_id)
{
    $qb = $this->createQueryBuilder('p');
    $qb->innerJoin('p.nursery', 'n')
        ->where('n.id = :id')
        ->andWhere('p.nurseryRole <> :profession')
        ->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));

    return $qb->getQuery()->getResult();
}

Answer 2

好的，謝謝Sepultura我的代碼工作！ 我點了這個：

public function findAllStaffLinkedToANursery($nursery_id)
{
    $qb = $this->createQueryBuilder('p');
    $qb->innerJoin('p.nurseries', 'n')
        ->where('n.id = :id')
        ->andWhere('p.nurseryRole <> :profession')
        ->setParameters(array('id' => $nursery_id, 'profession' => 'MANAGER'));

    return $qb->getQuery()->getResult();
}