[英]Javascript Loop inside another loop make 2 lists
我有一些看起來像這樣的數據:
{
"mains": [{
"id": "454",
"name": "main 1",
"subs": [{
"id": "32",
"name": "sub 1"
}, {
"id": "23",
"name": "sub 2"
}, {
"id": "54",
"name": "sub 3"
}],
"image": null
}, {
"id": "654",
"name": "main 2",
"subs": [{
"id": "87",
"name": "sub 1"
}, {
"id": "78",
"name": "sub 2"
}],
"image": null
}]
}
為此,我需要創建2個列表:
為了創建包含所有電源的第一個列表...我已經這樣做了:
mainlist = [];
sublist = [];
for (var i = 0; i < data.mains.length; i++) {
var obj = data.mains[i];
var mnlst = obj.name;
mainlist.push(mnlst);
}
console.log(mainlist);
在此示例中,它將返回市電名稱,從而產生2個名稱(在本例中)。
現在我需要做的是獲取每個主要對象的子名稱
因此,子列表(在這種情況下將返回)
主1的“ sub 1,sub 2和sub 3”,主2的“ sub 1和sub 2”等...
我怎樣才能做到這一點?
您實際上在問題標題中有一個正確的想法-嵌套循環,您需要像這樣迭代每個“ main”中的內部subs
:
mainlist = [];
sublist = {};
for (var i = 0; i < data.mains.length; i++) {
var obj = data.mains[i];
var mnlst = obj.name;
mainlist.push(mnlst);
var tempArr = [];
for(var j = 0; j < obj.subs.length ; j++){
var subObj = obj.subs[j];
var sblst = subObj.name;
tempArr.push(sblst);
}
sublist[mnlst] = tempArr;
}
我已將sublist
更改為對象,然后將“子”放入臨時數組中,然后再將它們作為鍵控數組(其中的鍵是主名稱)插入sublist
,現在可以像sublist['main 2']
以接收所有相關的訂閱
您可以對主name
為key的子列表使用其他數據結構。
var data = { "mains": [{ "id": "454", "name": "main 1", "subs": [{ "id": "32", "name": "sub 1" }, { "id": "23", "name": "sub 2" }, { "id": "54", "name": "sub 3" }], "image": null }, { "id": "654", "name": "main 2", "subs": [{ "id": "87", "name": "sub 1" }, { "id": "78", "name": "sub 2" }], "image": null }] }, mainlist = [], sublist = Object.create(null); data.mains.forEach(function (main) { mainlist.push(main.name); sublist[main.name] = main.subs.map(function (sub) { return sub.name; }); }) console.log(mainlist); console.log(sublist['main 1']); console.log(sublist);
.as-console-wrapper { max-height: 100% !important; top: 0; }
讓我們修改您的代碼。
mainlist = [];
sublist = [];
for (var i = 0; i < data.mains.length; i++) {
var obj = data.mains[i];
var mnlst = obj.name;
//--[Start Modification]--
var subArr = obj.subs;
for(var j = 0; j < subArr.length; j++)
{
var subName = subArr[i].name;
//Here you have subject name, do whatever you want to do with it.
}
//--[End Modification]--
mainlist.push(mnlst);
}
console.log(mainlist);
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