[英]Unable to show contact thumbnail image in tableview while using contacts framework in objective c
我正在使用UITableView顯示移動聯系人詳細信息,例如全名,電話號碼和個人資料圖像。 下面是代碼
- (void)viewDidLoad {
[super viewDidLoad];
[self fetchContactsandAuthorization];
[_selectContactListTblView reloadData];
}
-(void)fetchContactsandAuthorization
{
// Request authorization to Contacts
CNContactStore *store = [[CNContactStore alloc] init];
[store requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {
if (granted == YES)
{
//keys with fetching properties
NSArray *keys = @[CNContactFamilyNameKey, CNContactGivenNameKey, CNContactPhoneNumbersKey, CNContactImageDataKey];
NSString *containerId = store.defaultContainerIdentifier;
NSPredicate *predicate = [CNContact predicateForContactsInContainerWithIdentifier:containerId];
NSError *error;
NSArray *cnContacts = [store unifiedContactsMatchingPredicate:predicate keysToFetch:keys error:&error];
NSLog(@"new %@",cnContacts);
if (error)
{
NSLog(@"error fetching contacts %@", error);
}
else
{
NSString *phone;
NSString *fullName;
NSString *firstName;
NSString *lastName;
UIImage *profileImage;
NSMutableArray *contactNumbersArray = [[NSMutableArray alloc]init];
for (CNContact *contact in cnContacts) {
// copy data to my custom Contacts class.
firstName = contact.givenName;
lastName = contact.familyName;
if (lastName == nil) {
fullName=[NSString stringWithFormat:@"%@",firstName];
}else if (firstName == nil){
fullName=[NSString stringWithFormat:@"%@",lastName];
}
else{
fullName=[NSString stringWithFormat:@"%@ %@",firstName,lastName];
}
UIImage *image = [UIImage imageWithData:contact.imageData];
if (image != nil) {
profileImage = image;
}else{
profileImage = [UIImage imageNamed:@"person-icon.png"];
}
for (CNLabeledValue *label in contact.phoneNumbers) {
phone = [label.value stringValue];
if ([phone length] > 0) {
[contactNumbersArray addObject:phone];
}
}
NSDictionary* personDict = [[NSDictionary alloc] initWithObjectsAndKeys: fullName,@"fullName",profileImage,@"userImage",phone,@"PhoneNumbers", nil];
NSLog(@"persondictfull %@",personDict);
NSLog(@"persondictp %@",[personDict objectForKey:@"PhoneNumbers"]);
[contactFullNameArr addObject:[NSString stringWithFormat:@"%@",[personDict objectForKey:@"fullName"]]];
[contactPhoneNumberArr addObject:[NSString stringWithFormat:@"%@",[personDict objectForKey:@"PhoneNumbers"]]];
[contactImgPathArr addObject:[NSString stringWithFormat:@"%@",[personDict objectForKey:@"userImage"]]];
NSLog(@"contactImg - %@",contactImgPathArr);
}
dispatch_async(dispatch_get_main_queue(), ^{
[_selectContactListTblView reloadData];
});
}
}
}];
}
供參考,這是在contactImg日志中生成的內容
contactImg - (
"<UIImage: 0x7b935760>, {196, 199}",
"<UIImage: 0x7b77b1e0>, {196, 199}",
"<UIImage: 0x7b6d48a0>, {196, 199}",
"<UIImage: 0x7b6d4b40>, {196, 199}",
"<UIImage: 0x7b87d8e0>, {196, 199}",
"<UIImage: 0x7b87d950>, {3000, 2002}",
"<UIImage: 0x7b77b730>, {196, 199}",
"<UIImage: 0x7b77b9a0>, {196, 199}",
"<UIImage: 0x7b6d4c90>, {196, 199}",
"<UIImage: 0x7b87df10>, {196, 199}",
"<UIImage: 0x7b6d54a0>, {196, 199}",
"<UIImage: 0x7b9334c0>, {196, 199}"
)
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *simpleTableIdentifier = @"SelectContactTableViewCell";
SelectContactTableViewCell *cell = (SelectContactTableViewCell *)[tableView dequeueReusableCellWithIdentifier:simpleTableIdentifier];
if (cell == nil)
{
NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"SelectContactTableViewCell" owner:self options:nil];
cell = [nib objectAtIndex:0];
}
cell.contactFullName.text = [contactFullNameArr objectAtIndex:indexPath.row];
//tried by directly assigning the value but no use
cell.contactProfileImage.image = [contactImgPathArr objectAtIndex:indexPath.row];
//if i assign any static image i am able to see the image
// cell.contactProfileImage.image = [UIImage imageNamed:@"person-icon.png"];
cell.contactPhoneNumber.text = [contactPhoneNumberArr objectAtIndex:indexPath.row];
return cell;
}
我做了很多嘗試,但無法找出問題所在。 任何幫助將不勝感激。
你有幾個問題。 主要問題從這里開始:
[contactImgPathArr addObject:[NSString stringWithFormat:@"%@",[personDict objectForKey:@"userImage"]]];
personDict[@userImage"]
是一個UIImage
。由於某種原因,您可以通過圖像的description
方法創建一個字符串,並將該無用的字符串存儲在contactImgPathArr
。
稍后,您嘗試通過傳入圖像的描述來濫用UIImage imageNamed:
因此,您需要進行兩項更改。 首先,更改:
[contactImgPathArr addObject:[NSString stringWithFormat:@"%@",[personDict objectForKey:@"userImage"]]];
至:
[contactImgPathArr addObject:[personDict objectForKey:@"userImage"]];
(更好的是:)
[contactImgPathArr addObject:personDict[@"userImage"]];
然后更改:
cell.contactProfileImage.image = [UIImage imageNamed:[contactImgPathArr objectAtIndex:indexPath.row]];
至:
cell.contactProfileImage.image = [contactImgPathArr objectAtIndex:indexPath.row];
(甚至更好:)
cell.contactProfileImage.image = contactImgPathArr[indexPath.row];
順便說一句-您對personDict
的使用也毫無意義。
這段代碼:
NSDictionary* personDict = [[NSDictionary alloc] initWithObjectsAndKeys: fullName,@"fullName",profileImage,@"userImage",phone,@"PhoneNumbers", nil];
[contactFullNameArr addObject:[NSString stringWithFormat:@"%@",[personDict objectForKey:@"fullName"]]];
[contactPhoneNumberArr addObject:[NSString stringWithFormat:@"%@",[personDict objectForKey:@"PhoneNumbers"]]];
[contactImgPathArr addObject:[NSString stringWithFormat:@"%@",[personDict objectForKey:@"userImage"]]];
應該只是:
[contactFullNameArr addObject:fullName];
[contactPhoneNumberArr addObject:phone];
[contactImgPathArr addObject:profileImage];
當您可以簡單地使用someStringValue
時[NSString stringWithFormat:@"%@", someStringValue]
請勿使用[NSString stringWithFormat:@"%@", someStringValue]
。
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