我如何使這項工作？ 我不斷收到語法錯誤

Question

print("welcome to the password reset program")
print("please enter the new password")
input("type your new password")
input("type your new password (8-16 characters)")
password = input("type your new password (8-16 characters)")
    if password == <8
        print("this is too short, rethink, and re-enter your new password...")
    if password == >16
        print("this is too long, rethink, and re-enter your new password...")
    if password == 8-16
        print("this is the correct length, now re-enter to confirm")
password2 = input("re-enter your password")
    if password == password2
        print("your password has been changed")
    if password != password2
        print("this is not the same as your first password")

我收到“如果密碼== <8”的錯誤，你能幫我嗎？？？？

Answer 1

您需要使用len()比較密碼的長度。

您還需要使用<或<=來比較它而不是== ，並在 if 語句的末尾放置一個冒號。

所以你的代碼看起來像：

if len(password) <= 8:
    print("this is too short, rethink, and re-enter your new password...")
if len(password) >=16:
    print("this is too long, rethink, and re-enter your new password...")

你可以簡化為

if len(password) <= 8 or len(password) >= 16:
    print("Password must be between 8 and 16 characters, enter your new password...")

要讓用戶重新輸入密碼，您可以使用while循環直到他們的輸入有效：

while(len(password) <= 8 or len(password) >= 16):
    print("Password must be between 8 and 16 characters, enter your new password...")
    password=input("type your new password")

您可以再次使用它來檢查用戶輸入相同的密碼：

password2 = input("re-enter your password")
while password2!=password:
     password2=input("this is not the same as your first password")
print("your password has been changed")

正如其他用戶所提到的，您應該查看散列： https : //docs.python.org/3/library/hashlib.html

Answer 2

首先，沒有“x== < y”這樣的東西。 您正在尋找“x <= y”。

其次，如我之前的答案所述，您必須在 if 后添加 ':'。

你應該閱讀文檔。

Answer 3

print("welcome to the password reset program")
print("please enter the new password")
input("type your new password")
input("type your new password (8-16 characters)")
password = input("type your new password (8-16 characters)")
if len(password) <= 8:
    print("this is too short, rethink, and re-enter your new password...")
elif len(password) >= 16:
    print("this is too long, rethink, and re-enter your new password...")
else:
    print("this is the correct length, now re-enter to confirm")
    password2 = input("re-enter your password")
    if password == password2:
        print("your password has been changed")
    else:
        print("this is not the same as your first password")

正如其他人所建議的那樣，我會閱讀有關 Python 縮進以及如何使用 if/else 的文檔。

Answer 4

您的代碼有一些問題，我猜您可能有 JavaScript 背景。

問題如下。

1. 您缺少if語句末尾的: 。
2. 你不能在 Python 中使用== <或== > ，正確使用的是<=和>= 。
3. 您的if語句也有不正確的縮進。

更新了下面的代碼。

print("welcome to the password reset program")
print("please enter the new password")
input("type your new password")
input("type your new password (8-16 characters)")
password = input("type your new password (8-16 characters)")
if len(password) <= 8:
    print("this is too short, rethink, and re-enter your new password...")
if len(password) >= 16:
    print("this is too long, rethink, and re-enter your new password...")
if len(password) == (8-16): # is this a range or 8 - 16?
    print("this is the correct length, now re-enter to confirm")
password2 = input("re-enter your password")
if password == password2:
    print("your password has been changed")
if password != password2:
    print("this is not the same as your first password")

不要忘記散列密碼。 https://docs.python.org/3/library/hashlib.html

Answer 5

1. 您需要在每個 if、for 或 while 語句之后添加: 。
2. 運算符== <或== >不存在，您可以使用=>或<=代替
3. 在這一行中： if password == 8-16您可以使用運算符in來評估變量是否在列表中，例如if len(password) in range(8-16)

在你的情況下可能是

if password <= 8
        print("this is too short, rethink, and re-enter your new password...")
    if password >= 16
        print("this is too long, rethink, and re-enter your new password...")
    if len(password) in range(8, 16)
        print("this is the correct length, now re-enter to confirm")
password2 = input("re-enter your password")
    if password == password2
        print("your password has been changed")
    if password != password2
        print("this is not the same as your first password")