[英]How can i add as well as remove layout pragmatically in android?
我想作為AutoCompleteTextview工作。 但我沒有在我的項目中使用自動完整文本視圖。 我使用了編輯文本,並使用適配器的值對適配器的值進行排序,我正在創建一個動態按鈕。 但實際上,我想刪除動態創建的按鈕。 當用戶在編輯文本中輸入新值時,它會根據必須創建的按鈕在適配器中對新值進行排序。 但是,我的問題是,當用戶在編輯文本視圖上輸入新文本時,不會刪除動態創建的按鈕。 它必須看起來像這樣:
if (!s.equals("")) {
final String query = s.toString().trim();
filteredTags.clear();
((ViewManager) btnTag.getParent()).removeView(btnTag);
for (int i = 0; i < TagArray.size(); i++) {
final String tagName = TagArray.get(i).gettagName();
if (tagName.contains(query)) {
filteredTags.add(TagArray.get(i));
}
}
count1 = filteredTags.size();
layout = (LinearLayout) dialog.getCustomView().findViewById(R.id.layoutTags);
layout.setOrientation(LinearLayout.VERTICAL); //Can also be done in xml by android:orientation="vertical"
layout.setWeightSum(1);
float rowneed = ((float) count1 / 5);
k = 0;
for (int i = 0; i < ceil(rowneed); i++) {
row1 = new LinearLayout(getContext());
row1.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.WRAP_CONTENT, LinearLayout.LayoutParams.WRAP_CONTENT));
/* layout.setVisibility(View.VISIBLE);
row.setVisibility(View.VISIBLE);*/
for (int j = 0; j < 5; j++) {
btnTag = new Button(getContext());
btnTag.setHeight(15);
btnTag.setWidth(0);
btnTag.setMinimumWidth(155);
btnTag.setMinimumHeight(135);
mTagList1 = new ArrayList<>();
if (k < count1) {
btnTag.setText(filteredTags.get(k).gettagName());
btnTag.setId(k);
k++;
btnTag.setVisibility(View.VISIBLE);
} else {
btnTag.setVisibility(View.INVISIBLE);
}
Log.e("count", " " + k + " " + count1 + " " + ceil(rowneed) + " " + edtTag.getText().toString());
btnTag.setTextSize(7);
btnTag.setGravity(0);
row1.addView(btnTag);
}
layout.addView(row1);
}
for (int btnId = 0; btnId < filteredTags.size(); btnId++) {
btnTag = (Button) dialog.getCustomView().findViewById(btnId);
final int finalId1 = btnId;
btnTag.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
TagNameArray.add(new Tags(filteredTags.get(finalId1).gettagId(), filteredTags.get(finalId1).gettagName()));
// Log.e("button","Button clicked index = " + finalId +" "+ TagArray.get(finalId1).gettagName()+" "+TagNameArray.size());
}
});
}
}
添加以下代碼行:
layout.removeAllViews(); layout.invalidate(); row.removeAllViews(); row.invalidate();
這可能會對你有所幫助,給我一個反饋,希望我幫助你
例如,為btnTag設置動態標簽
btnTag.setTag(DynamicTagInt++);
然后
row1.removeView(btnTag.findViewById(DynamicTagInt));
//DynamicTagInt= the desired button that you want to delete
或者按例如按鈕的ID
row1.removeView(btnTag.findViewWithTag(k));
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.