XMPP：如何解析XMPPMessage元素
[英]XMPP: How to parse XMPPMessage element
問題描述
對於來自xmpp的每條消息，我都獲得以下xml格式
- (void)xmppStream:(XMPPStream *)sender didReceiveMessage:(XMPPMessage *)message
{
NSLog(@"Message %@",message);
}
在控制台上打印
<message
xmlns="jabber:client" from="10000006956@xmpp-dev.peeks.com" to="10000006956@xmpp-dev.peeks.com/mobile">
<result
xmlns="urn:xmpp:mam:tmp" id="1483781596098940">
<forwarded
xmlns="urn:xmpp:forward:0">
<message
xmlns="jabber:client" from="10000006931@xmpp-dev.peeks.com/mobile" to="10000006956@xmpp-dev.peeks.com" type="chat">
<body>Hi</body>
<delay
xmlns="urn:xmpp:delay" from="xmpp-dev.peeks.com" stamp="2016-12-22T04:50:17.023Z">Offline Storage
</delay>
</message>
<delay
xmlns="urn:xmpp:delay" from="xmpp-dev.peeks.com" stamp="2017-01-07T09:33:16.099Z">
</delay>
</forwarded>
</result>
</message>
我想從每條消息中提取“從”，“到”，“正文”和“戳記”，然后執行以下操作
NSXMLElement *body = message;
NSXMLElement *messageb = [body elementForName:@"result" xmlns:@"urn:xmpp:mam:tmp"];
NSXMLElement *forwa=[messageb elementForName:@"forwarded" xmlns:@"urn:xmpp:forward:0"];
NSXMLElement *msg=[forwa elementForName:@"message" xmlns:@"jabber:client"];
NSXMLElement *TD=[forwa elementForName:@"delay" xmlns:@"urn:xmpp:delay"];
NSString *from=[[msg elementForName:@"from" xmlns:@"jabber:client"] stringValue];
NSString *to=[[msg elementForName:@"to" xmlns:@"jabber:client"] stringValue];
NSString *bodyq=[[msg elementForName:@"body"] stringValue];
NSString *stmp=[[TD elementForName:@"stamp" xmlns:@"urn:xmpp:delay"] stringValue];
NSString *final=[NSString stringWithFormat:@"From: %@\nTo: %@\nBody: %@\nStamp: %@",from,to,bodyq,stmp];
NSLog(@"forwa %@", final);
我只能打印郵件正文，日志打印如下
From: (null)
To: (null)
Body: hi
Stamp: (null)
2 個解決方案
解決方案1
1 已采納 2017-01-10 11:11:22
修復了搜索屬性的問題：元素是節點（例如Body，Result等），而其他元素只是先前元素的屬性。
NSString *from=[[msg attributeForName:@"from"] stringValue];
NSString *to=[[msg attributeForName:@"to"] stringValue];
NSString *stmp=[[TD attributeForName:@"stamp"] stringValue];
編輯（對不起，我與ObjectiveC的最后合作真的很舊）。
xml namespace它是關於element而不是attributes 。
如果沒有再嘗試，請嘗試通過NSXMLNode
NSXMLNode *fromNode = [msg attributeForName:@"from"];
NSString *from = [fromNode stringValue];
解決方案2
1 2019-04-17 11:06:52
快速5：
func xmppStream(_ sender: XMPPStream, didReceive message: XMPPMessage) {
if let msg = message.body {
if let from = message.attribute(forName: "from")?.stringValue{
print("msg: \(msg), \(from)")
}
}
}
如何在XMPP中接受好友請求？
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