擴展 Angular 服務/工廠以獲取日期數組和整數數組，並創建具有鍵值對的數組

Question

我有一個服務/工廠，它接受一組日期，並根據 ISO 周將其分組在一組數組[[],[]] 。 此功能按預期工作。

但是如何擴展服務/工廠以獲取另一個值數組（只是普通的整數值），並創建每個 date 和 value 的鍵值對。 仍然是數組數組的相同輸出格式？

這是我的服務/工廠電話：

$scope.weeks = GroupDateRangeService.createArray(timeline_data, time_trend);

傳遞給服務的數據如下所示：

timeline_data: ["2017-01-04","2017-01-05","2017-01-06","2017-01-07","2017-01-08","2017-01-09","2017-01-10","2017-01-11"]

time_trend: [566, 607, 430, 357, 277, 591, 711, 206]

結果看起來像這樣：

result: [["2017-01-04": 566,"2017-01-05": 607,"2017-01-06": 430,"2017-01-07": 357,"2017-01-08": 277], ["2017-01-09": 591,"2017-01-10": 711,"2017-01-11": 206]]

這是我的服務/工廠：

(function () {
    'use strict';

    angular
        .module('portalDashboardApp')
        .factory('GroupDateRangeService', GroupDateRangeService);

    GroupDateRangeService.$inject = [];

    function GroupDateRangeService() {

        var service = {
            createArray: createArray,
        };

        return service;

        function createArray(data) {
            var arr = data.map(function (s) {
                var week = getWeekNumber(parseISOLocal(s));
                return week[0] + ('0' + week[1]).slice(-2) + ':' + s;
            }).sort();
            return createGroupedArray(createGroupObject(arr));
        };

        function createGroupObject(arr) {

            var groupedObj = arr.reduce(function (result, value) {

                var b = value.split(':');

                if (!result[b[0]]) result[b[0]] = [];
                result[b[0]].push(b[1]);

                return result;

            }, {});

            return groupedObj;
        };

        function createGroupedArray(groupedObj) {

            // Grab arrays in order of week number. Sort keys to maintain order
            var groupedArray = Object.keys(groupedObj).sort().map(key=>groupedObj[key]);

            return groupedArray;
        }

        /* Helper to get the ISO week number of a date
        ** @param {Date} date to get week of
        ** @returns {Array} [year, weekNumber]
        */
        function getWeekNumber(d) {
            d = new Date(+d);
            d.setHours(0, 0, 0, 0);
            d.setDate(d.getDate() + 4 - (d.getDay() || 7));
            var yearStart = new Date(d.getFullYear(), 0, 1);
            var weekNo = Math.ceil((((d - yearStart) / 86400000) + 1) / 7);
            return [d.getFullYear(), weekNo];
        }

        /* Parse ISO 8601 format date string to local date
        ** @param {string} s - string to parse like 2016-12-15
        ** @returns {Date}
        */
        function parseISOLocal(s) {
            var b = s.split(/\D/);
            return new Date(b[0], b[1] - 1, b[2]);
        }
    }

})();

我將不勝感激您的指導！

Answer 1

認為這是您的合並例程（更新以顯示如何使用內部數組與提供的數組，以及如何切換處理指令）：

// These arrays were already made by your service
let premadeKeys = [ 'pre', 'made', 'keys' ];
let premadeVals = [ 'val1', 'val2', 'val3' ];

// Formatrules is a naive way to switch how you want it processed, could be any enum etc.
function mergeArrays ( keys = premadeKeys, values = premadeVals, formatRules = 0 ) {
   switch ( formatRules ) {
        case 0:
            return keys.map ( ( d, i ) => {
                let obj = {};
                obj [ d ] = values [ i ];
                return obj;
            } ); 
        case 1:
            return keys.map ( ( d, i ) => {
                let obj = {};
                obj [ d ] = values [ i ] + '_TAIL_' + i;
                return obj;
            } );    

   }
}

let arr1 = [ "a", "b", "c" ];
let arr2 = [ 1, 2, 3 ];
// provided arrays
console.log ( mergeArrays ( arr1, arr2 ) );
console.log ( mergeArrays ( arr1, arr2, 1 ) );
// pre made arrays
console.log ( mergeArrays ( ) );
console.log ( mergeArrays ( undefined, undefined, 1 ) );

Answer 2

您的結果不能像那樣，數組不能有鍵值對。 它必須是一組對象數組。 如果重構函數以接受第二個參數，則可以執行以下操作：

function createArray(data, optionalTimeTrend) {
    var arr = data.map(function (s) {
        var week = getWeekNumber(parseISOLocal(s));
        return week[0] + ('0' + week[1]).slice(-2) + ':' + s;
    }).sort();
    var results = createGroupedArray(createGroupObject(arr));
    if (optionalTimeTrend && optionalTimeTrend.length === data.length) {
        for (var i = 0; i < results.length; i++) {
            results[i] = results[i].map(function (date, index) {
                var obj = {};
                obj[date] = optionalTimeTrend[index];
                return obj;
            });
        }
    }
    return results;
};

你的結果應該是這樣的：

result: [[{"2017-01-04": 566},{"2017-01-05": 607},{"2017-01-06": 430},{"2017-01-07": 357},{"2017-01-08": 277}], [{"2017-01-09": 591},{"2017-01-10": 711},{"2017-01-11": 206}]]