[英]Stand alone method is calling another method by itself
好的,每當我想從方法中返回一些東西時,我都會認真地將方法傳遞給方法。 你們能解釋一下我如何通過它。 這是我的哈希
$choosen_gun = {}
$Weapon = {
:Bazoka => ["Bazoka",5],
:Machine_gun => ["Machine_gun",1000],
:Hand_gun => ["Hand_gun",24,2],
:Double_Hand_gun => ["Double_Hand_gun",24,4],
:Sniper => ["Sniper",12,1],
:Shot_gun => ["Shot_gun",8,2]
}
這是我的方法武器的代碼
def Weapon
puts "Now it's time to select your weapon."
puts "Please choose a weapon that is good throughout the game."
puts "Whenever you are shortage of bullets, please reload it."
puts "Please avoid last minute of reloading of weapon."
puts "Now choose your weapon based on your own preferences."
print "\n"
puts "Type 1"
puts "Gun Name: Bazoka"
puts "Description: A powerful gun that is strong with only 5 bullets."
puts "Rating: ★ ★ ★ ★"
num = gets.chomp.to_i
case num
when 1
puts "Selection of Bazoka is chosen"
puts "Loaded 5 bullets only"
$choosen_gun[num] = $Weapon[:Bazoka]
end
return num
end
調用方法后。 用戶將選擇他的武器,並將其添加到num的$ choosen_gun哈希中,並返回用戶鍵入的num。
這是我的方法ZombieRoom的代碼
def ZombieRoom(w)
zombie = {
:Construcied => [5],
:Invader => [5],
:Damned => [5],
:Steampunk => [5],
:Stoner => [5],
:Wasted => [5],
:Romero => [5]
}
puts "Welcome to the worst night mare of Zombie Room"
puts "You will be fighting with a random zombie"
while true
puts ".........."
puts "Selecting a random zombie"
puts "Selecting your prefered gun...."
case w
when 1
$choosen_gun[1]
puts "Your selected gun is #{$choosen_gun[1][0]}"
#values = zombie.values
#puts values[rand(values.size)]
#random_zombie = zombie.keys.sample(1)
#puts random_zombie[
random_zombie = zombie.to_a.sample(1).to_h
random_zombie.each do |key,value|
puts "Your random zombie is #{key}"
puts "With a health value of #{value[0]}"
puts "Time to take down that zombie now."
while true
puts "Type Shoot to knock it down or quit."
choice = gets.chomp
if $choosen_gun[1][1] >= 1
health = value[0] -= 1
$choosen_gun[1][1] -= 1
puts "#{key} health now is #{health}"
else
puts "Please reload your gun"
puts "Reloading......"
$choosen_gun[1][1] += 5
end
if health == 0
puts "You have defeated #{key}"
puts "Congrats!!!"
puts "We are happy for you"
puts "Lets begins to collect your prize"
CollectPrize()
else
puts "You did not defeat the #{key} yet"
end
end
end
end
end
end
這是我的方法CollectPrize的代碼
def CollectPrize
puts "Congratulations on defeating"
puts "We would now like to give you some case prizes"
print "\n"
puts "Please choose only 1 prize for yourself"
print "\n"
puts "Type 1"
puts "$50,000"
print "\n"
puts "Type 2"
puts "$25,000"
print "\n"
puts "Type 3"
puts "$55,000"
hoho = gets.chomp.to_f
if hoho == 1
puts "hehe"
end
end
在這里我怎么稱呼我的方法
ZombieRoom(Weapon())
CollectPrize()
現在的問題是,每當調用CollectPrize方法並輸入我的輸入以收集獎賞示例1時,它就會顯示“ $ 50,000”。 而不是結束問題,它返回到ZombieRoom並繼續循環播放“ Type Shoot將其擊倒或退出”。 至少有人可以告訴我解決此問題的正確方法還是通過其他方法傳遞方法嗎?
在紅寶石常量中,以大寫字母開頭。 方法始終以小寫形式定義。
在irb中嘗試這個
irb(main):001:0> def Weapon
irb(main):002:1> end
=> :Weapon
irb(main):003:0> Weapon
NameError: uninitialized constant Weapon
要使用ruby的命名約定解決您的問題名稱方法:
zombie_room
, collect_prize
等。
然后這段代碼將起作用:
zombie_room(weapon())
您在做什么並沒有真正將方法武器傳遞給方法僵屍室。 真正發生的是執行了方法武器,然后返回一個值,並將該值的結果傳遞給方法zombie_room。
我認為這就是您想要的。
如果需要傳遞方法,請查看proc
和lambda
文檔,或者僅使用塊。
您的代碼處於一個大while true
循環中。 由於true始終為true,因此它將永遠不會結束,因此在調用CollectPrize()之后,它僅返回while
語句。
您可以通過在CollectPrize()
之后插入一個break
來擺脫掉它,但是圍繞此循環還有另一個while true
循環。
我認為您需要更加注意如何退出while循環。
puts "Time to take down that zombie now."
while true # <---------------- this is ALWAYS going to loop, without end
puts "Type Shoot to knock it down or quit."
choice = gets.chomp
if $choosen_gun[1][1] >= 1
health = value[0] -= 1
$choosen_gun[1][1] -= 1
puts "#{key} health now is #{health}"
else
puts "Please reload your gun"
puts "Reloading......"
$choosen_gun[1][1] += 5
end
if health == 0
puts "You have defeated #{key}"
puts "Congrats!!!"
puts "We are happy for you"
puts "Lets begins to collect your prize"
CollectPrize()
else
puts "You did not defeat the #{key} yet"
end
end
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