指針和二進制搜索樹

Question

我正在使用二進制搜索樹（作為練習）的程序上工作。 我的問題是，當我嘗試添加一個客戶時 （在我的代碼行65-69的中間），盡管我在此函數中插入了struct BST_node * root，但我收到未聲明BS_node的錯誤。我的部分代碼如下，只是為了讓讀者閱讀更容易，如果需要，我可以上傳完整代碼！ 謝謝！

  #include <stdio.h>
  #include <stdlib.h>
  #include <string.h>

#define MAX_STRING 50

void flush();

struct customer {
    char *name;
    char *address;
    char *email;
};

    struct double_linked_list {
    struct customer *data;
    struct double_linked_list *previous;
    struct double_linked_list *next;
};

    struct double_linked_list *customers_head=0;

    struct BST_node {
    struct double_linked_list *data;
    struct BST_node *left;
    struct BST_node *right;
};

    struct BST_node *BST_email_root = 0;

    struct BST_node *BST_find_customer(struct BST_node *root, char *email) {
    if (root==NULL)
        return NULL;
    if (strcmp(email,root->data->data->email)==0)
        return root;
    else
    {
    if (strcmp(email,root->data->data->email)==-1)
        return BST_find_customer(root->left,email);
    else
        return BST_find_customer(root->right,email);
    }
}

    void find_customer() {
    char email[MAX_STRING];
    struct double_linked_list *l;
    struct BST_node *b;
    printf("Give the email of the customer (up to %d characters) : ", MAX_STRING-1);
    gets(email);

    b = BST_find_customer(BST_email_root, email);
    if (b==0)
        printf("There is no customer with this email.\n");
    else
    {
        l = b->data;
        printf("Customer found! \n");
        printf("Name    : %s\n", l->data->name);
        printf("Address : %s\n", l->data->address);
        printf("Email   : %s\n", l->data->email);
    }
}

struct BST_node *new_BST_node(struct BST_node *root, struct double_linked_list *l)
{
if (root==NULL);
    {
    root = (BST_node *) malloc (sizeof(BST_node ));
    if (root==NULL)
        {
        printf("Out of Memory!");
        exit(1);
        }
    root->data=l;
    root->left=NULL;
    root->right=NULL;
    }

if (strcmp(l->data->email,root->data->data->email)==-1)
            root->left =new_BST_node(root->left,l);
else root->right =new_BST_node(root->right,l);

return root;
};

struct double_linked_list *new_customer()
{
    char name[MAX_STRING], address[MAX_STRING], email[MAX_STRING];
    struct BST_node *b;
    struct double_linked_list *l;
    struct customer *c;

    printf("\nADDING NEW CUSTOMER\n=\n\n");
    printf("Give name (up to %d characters): ", MAX_STRING-1);
    gets(name);

    printf("Give address (up to %d characters): ", MAX_STRING - 1);
    gets(address);

    printf("Give email (up to %d characters): ", MAX_STRING - 1);
    gets(email);


    b = BST_find_customer(BST_email_root, email);
    if (b)
    {
        printf("Duplicate email. Customer aborted.\n");
        return 0;
    }

    c = (struct customer *) malloc(sizeof(struct customer));
    if (c == 0)
    {
        printf("Not enough memory.\n");
        return 0;
    }

    c->name = strdup(name); // check for memory allocation problem
    if (c->name == 0) return 0;
    c->address = strdup(address);   // check for memory allocation problem
    if (c->address == 0) return 0;
    c->email = strdup(email);   // check for memory allocation problem
    if (c->email == 0) return 0;

    l = (struct double_linked_list*) malloc(sizeof(struct double_linked_list));
    if (l == 0)
    {
        printf("Not enough memory.\n");
        free(c->name);
        free(c->address);
        free(c->email);
        free(c);
        return 0;
    }

    l->data = c;
    l->previous = 0;
    l->next = customers_head;

    if (customers_head)
        customers_head->previous = l;

    customers_head = l;

    BST_email_root = new_BST_node(BST_email_root, l);

    return l;
}

void displaymenu() {
    printf("\n\n");
    printf("1. New customer\n");
    printf("2. Find customer using email\n");
    printf("0. Exit\n\n");
    printf("Give a choice (0-6) : ");
}

    void flush()
{
    char ch;
    while ((ch = getchar()) != '\n' && ch != EOF);
}


int main() {
int choice;
do {
    displaymenu();
    scanf("%d", &choice);
    flush();
    switch (choice) {
    case 1:
        new_customer();
        break;
    case 2:
        find_customer();
        break;
} while (choice != 0);

return 0;
}

Answer 1

在第69行，您必須指定struct BST_node而不是BST_node ：

root = (struct BST_node *) malloc (sizeof(struct BST_node ));

至於代碼的其余部分：閱讀手冊gets ，這顯然是一個功能一個不應該使用，我建議用替換它fgets 。 最后一個switch （第178行）中還缺少一個右括號。