如何在Have子句下進行多次計數

Question

一些樣本數據：

Id    name    value    ref
1     ab      xy
2     aba     z
3     ab      xy
4     abc     def
5     gxr     mdy

我想做的是使出現兩次以上的兩列，以便選擇第1行和第3行。

select name, value from table_x 
where value is not null group by name having count(name) >= 2 
and having count(value) >= 2;

卡住了.....

Answer 1

如果只關心查找出現多次的不同名稱/值對，則@vkp的答案是正確的。 但是，如果您實際上希望滿足條件的各個行，請嘗試以下操作：

SELECT  t1.Name, t1.[Value]
FROM    Table_X t1
JOIN
(
    SELECT  Name, [Value]
    FROM    Table_X
    where   [Value] IS NOT NULL
    GROUP   BY Name, [Value]
    HAVING  COUNT(1) >= 2
) t2 ON t1.Name = t2.Name AND t1.[Value] = t2.[Value]

Answer 2

您的語法不正確。 group by名稱和值group by然后檢查計數> = 2。

select name, value 
from table_x 
where value is not null 
group by name, value 
having count(*) >= 2;