[英]javax.crypto.BadPaddingException: Decryption error
這是運行我的編碼和解碼類時遇到的錯誤。
javax.crypto.BadPaddingException: Decryption error
at sun.security.rsa.RSAPadding.unpadV15(RSAPadding.java:380)
at sun.security.rsa.RSAPadding.unpad(RSAPadding.java:291)
at com.sun.crypto.provider.RSACipher.doFinal(RSACipher.java:365)
at com.sun.crypto.provider.RSACipher.engineDoFinal(RSACipher.java:391)
at javax.crypto.Cipher.doFinal(Cipher.java:2087)
at RSAEncDecDemo.decryptData(RSAEncDecDemo.java:64)
at RSAEncDecDemo.main(RSAEncDecDemo.java:47)
java.lang.NullPointerException
at java.lang.String.<init>(String.java:556)
at RSAEncDecDemo.decryptData(RSAEncDecDemo.java:70)
at RSAEncDecDemo.main(RSAEncDecDemo.java:47)
這是RSAEncDecDemo.java類文件的源代碼。
public class RSAEncDecDemo {
private static final String PUBLIC_KEY_FILE = "lk.public.key";
private static final String PRIVATE_KEY_FILE = "lk.private.key";
@SuppressWarnings("restriction")
public static void main(String[] args) throws IOException {
try {
KeyPairGenerator keyPairGenerator = KeyPairGenerator.getInstance("RSA");
keyPairGenerator.initialize(2048);
KeyPair keyPair = keyPairGenerator.generateKeyPair();
PublicKey publicKey = keyPair.getPublic();
PrivateKey privateKey = keyPair.getPrivate();
writeStringkey(PUBLIC_KEY_FILE,new BASE64Encoder().encode(publicKey.getEncoded()));
writeStringkey(PRIVATE_KEY_FILE,new BASE64Encoder().encode(privateKey.getEncoded()));
String demoString = "123346";
RSAEncDecDemo rsa = new RSAEncDecDemo();
String decrypted = rsa.decryptData(demoString);
String msisdn = decrypted.substring(0,decrypted.indexOf("|"));
} catch (Exception e) {
e.printStackTrace();
}
}
private String decryptData(String strData) throws IOException {
byte[] data = DatatypeConverter.parseHexBinary(strData);
byte[] descryptedData = null;
try {
PrivateKey privateKey = readPrivateKeyFromFile(PRIVATE_KEY_FILE);
Cipher cipher = Cipher.getInstance("RSA");
cipher.init(Cipher.DECRYPT_MODE, privateKey);
descryptedData = cipher.doFinal(data);
} catch (Exception e) {
e.printStackTrace();
}
return new String(descryptedData);
}
@SuppressWarnings("restriction")
public PrivateKey readPrivateKeyFromFile(String fileName)throws IOException, NoSuchAlgorithmException,InvalidKeySpecException {
String publicK = readStringKey(fileName);
byte[] keyBytes = new BASE64Decoder().decodeBuffer(publicK);
PKCS8EncodedKeySpec keySpec = new PKCS8EncodedKeySpec(keyBytes);
KeyFactory fact = KeyFactory.getInstance("RSA");
return fact.generatePrivate(keySpec);
}
public PrivateKey readPrivateKeyFromFileold(String fileName)throws IOException {
FileInputStream fis = null;
ObjectInputStream ois = null;
try {
fis = new FileInputStream(new File(fileName));
ois = new ObjectInputStream(fis);
BigInteger modulus = (BigInteger) ois.readObject();
BigInteger exponent = (BigInteger) ois.readObject();
RSAPrivateKeySpec rsaPrivateKeySpec = new RSAPrivateKeySpec(modulus, exponent);
KeyFactory fact = KeyFactory.getInstance("RSA");
PrivateKey privateKey = fact.generatePrivate(rsaPrivateKeySpec);
return privateKey;
} catch (Exception e) {
e.printStackTrace();
} finally {
if (ois != null) {
ois.close();
if (fis != null) {
fis.close();
}
}
}
return null;
}
public static void writeStringkey(String fileName, String data) {
try {
FileWriter out = new FileWriter(new File(fileName));
out.write(data);
out.close();
} catch (IOException e) {
}
}
public static String readStringKey(String fileName) {
BufferedReader reader = null;
StringBuffer fileData = null;
try {
fileData = new StringBuffer(2048);
reader = new BufferedReader(new FileReader(fileName));
char[] buf = new char[1024];
int numRead = 0;
while ((numRead = reader.read(buf)) != -1) {
String readData = String.valueOf(buf, 0, numRead);
fileData.append(readData);
buf = new char[1024];
}
reader.close();
} catch (Exception e) {
} finally {
if (reader != null) {
reader = null;
}
}
return fileData.toString();
}
}
錯點在哪里? 解密部分就是給那個錯誤。
全班上傳到這里鏈接到源代碼
-謝謝
原則上,密文應該與隨機無區別。 也就是說,密碼確實會對域(大小和可能的值)施加約束。 對於RSA PKCS#1-這是Oracle提供程序中“ RSA”的默認模式-輸出必須恰好是密鑰大小(以字節為單位)。 此外,該值必須小於模數。
現在,假設您剛剛向我們顯示了演示值(因為異常與輸入不匹配),並且密文的大小正確。 在這種情況下,您將在以下任一情況下獲得未填充的異常:
您將不得不嘗試直到找到罪魁禍首,如果沒有必需的信息,我們將無法為您進行測試。
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