![](/img/trans.png)
[英]Extract json string array value from json object using java
[英]How to extract a subset of json array from value in sub array, in java?
以下是我的json:
{
"id": null,
"extId": "720916740",
"legacyId": null,
"customerId": null,
"accountId": null,
"clientId": null,
"publisherId": null,
"name": "AllColumns1_1482141239819",
"status": "ACTIVE",
"operationStatus": null,
"startDate": "20180101",
"endDate": null,
"channel": "SEARCH",
"lastSyncDate": null,
"linkStatus": "NOT_LINKED"
},
{
"id": null,
"extId": "720916743",
"legacyId": null,
"customerId": null,
"accountId": null,
"clientId": null,
"publisherId": null,
"name": "AllColumns2_1482141239819",
"status": "ACTIVE",
"operationStatus": null,
"startDate": "20180101",
"endDate": null,
"channel": "SEARCH",
"lastSyncDate": null,
"linkStatus": "NOT_LINKED"
},
{
"id": null,
"extId": "720933833",
"legacyId": null,
"customerId": null,
"accountId": null,
"clientId": null,
"publisherId": null,
"name": "2TestCamp2_1482149078243",
"status": "ACTIVE",
"operationStatus": null,
"startDate": "20180101",
"endDate": null,
"channel": "SEARCH",
"lastSyncDate": null,
"linkStatus": "NOT_LINKED"
}
從上面的json,我想獲取名稱為“ 2TestCamp2_1482149078243”的id和extid。 我如何在JAVA中獲得它?
通常,首先要從json數組中找到該子數組,其值為“ 2TestCamp2_1482149078243”; 然后從該子數組獲取鍵id和ext id的值。
謝謝。 如果有人在這方面幫助我,那將很好。 我是java和json的新手。
String validate_name="2TestCamp2_1482149078243";
JSONObject object = new JSONObject(YOUR-JSON-Object);
JSONArray getArray = object.getJSONArray("Result");
for(JSONObject value:getArray) //For Each loop to iterate the Objects from JSONArray
{
if(value.getString("name").equals(validate_name))
{
value.getString("id");
value.getString("extId");
}
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.