Postgres獲取列組中至少有一個特定值的行由另一列

Question

我有一個sql命令：

select location,status,total from my_table

這個回報：

location - status - total
city a - active - 3
city a - pending - 2
city a - cancel - 4
city b - pending - 4
city b - cancel - 4
city c - active - 2
city c - cancel - 6

如何僅返回城市中至少有一次狀態為活動且總數> = 1的行？

所以，我想回歸：

    location - status - total
    city a - active - 3
    city a - pending - 2
    city a - cancel - 4
    city c - active - 2
    city c - cancel - 6

當你注意到我不想返回城市b因為它至少有一次活動狀態沒有活動，總數> = 1。

Answer 1

select location,status,total from my_table
where location in (
    select location from my_table
    where status = 'active'
        and total >= 1
    )