[英]Regular Expression to find <>
我有一個字符串
"Absolutely<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E64> Friendship goals exceeded here!! Sydney, Melbourne, Connecticut & South Carolina<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E61>\r\n"
我只想將 <> 部分與字符串分開。 我試過<.*>
但它回來了
<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E64> Friendship goals exceeded here!! Sydney, Melbourne, Connecticut & South Carolina<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E61>
我不要他們之間的話。 我想要輸出,
["<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E64>", "<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E61>"]
任何幫助。 我被困在 python 中。
你需要一個負面的前瞻。 此模式匹配,直到找到第一個>
后面沒有<
:
import re
text = "Absolutely<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E64> Friendship goals exceeded here!! Sydney, Melbourne, Connecticut & South Carolina<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E61>\r\n"
pattern = "<.*?>(?!<)"
print re.findall(pattern, text)
#['<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E64>', '<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E61>']
您可以使用<.*?>(?!<)
而不是<.*>
。
這是你可以做的
s = "Absolutely<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E64> Friendship goals exceeded here!! Sydney, Melbourne, Connecticut & South Carolina<U+653C><U+3E64><U+613C><U+3E30><U+623C><U+3E64><U+653C><U+3E64><U+623C><U+3E31><U+383C><U+3E61>\r\n"
result = re.findall('<.*?>(?!<)',s)
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