多重加入codeigniter

Question

這里有三個表，即tbl_users ， tbl_account_details ， tbl_attendance .table tbl_users看起來像這樣

user_id     username            role_id     activated   banned  
    1        admin                  1           1         0         
    36       siraj                  3           1         0     
    37       faizal                 3           1         0     
    38       nesru                  3           1         0     
    40       jaseer                 3           1         0     
    42       maltu                  3           1         0     
    43       shahul                 3           1         0 

表tbl_account_details看起來像這樣

account_details_id  user_id     fullname        designations_id     
    1                 1       Administrator         1   
    33                36        siraj               2   
    34                37        faizal              3   
    35                38        nesru               3   
    37                40        jaseer              4   
    39                42        maltu               4   
    40                43        shahul              2   

我的tbl_attendance表看起來像這樣

attendance_id   user_id      date_in        attendance_status status 0=absent 1=present 3 = onleave 4 = onoff
    1            1          2017-02-05      1
    2            36         2017-02-11      4
    3            36         2017-02-11      4
    4            36         2017-02-11      3
    5            1          2017-02-02      1
    6            36         2017-02-01      1

我想所有users ，其中users是不是在onleave和onoff在當天的tbl_attendance請假.the出勤狀況是3和關閉是4為了得到我寫了一個查詢，看起來像這樣

public function get_manager_cordinator_users($date)
{

     $this->db->select('tbl_account_details.*', FALSE);
     $this->db->select('tbl_users.*');
     $this->db->join('tbl_account_details', 'tbl_users.user_id = tbl_account_details.user_id', 'left');
     $this->db->where(array('designations_id' => 2));
     $this->db->or_where(array('designations_id' => 3));
     $this->db->where('tbl_users.user_id NOT IN(SELECT user_id FROM tbl_attendance WHERE tbl_attendance.date_in='.$date.' && attendance_status=3 OR attendance_status=4 )');
     $query_result = $this->db->get('tbl_users');
     $result = $query_result->result();
     return $result;


}

 my controller looks like this 


$date=date('Y-m-d');
$data['assign_user'] = $this->Project_model->get_manager_cordinator_users($date);

請幫我解決...

Answer 1

我創建了一個查詢，它將返回具有 designation_id 2 和 3 的用戶數據，這些用戶也沒有參與狀態 3 和 4

你的控制器代碼很好 -

$date = date('Y-m-d');
$data['assign_user'] = $this->Project_model->get_manager_cordinator_users($date);

只需使用以下代碼更改您的型號代碼 -

public function get_manager_cordinator_users($date)
{
  $this->db->select( 'tbl_users.user_id, tbl_users.username,tbl_account_details.designations_id, tbl_attendance.date_in, tbl_attendance.attendance_status' );
  $this->db->from( 'tbl_users' );
  $this->db->join( 'tbl_account_details', 'tbl_account_details.user_id = tbl_users.user_id' );
  $this->db->join( 'tbl_attendance', 'tbl_attendance.user_id = tbl_users.user_id' );
  $this->db->where( 'tbl_attendance.date_in', $date );
  $this->db->where('tbl_users.banned', 0);
  $this->db->where('tbl_users.activated', 1);
  $this->db->where_in( 'tbl_account_details.designations_id', array( '2', '3' ) );
  $this->db->where_not_in( 'tbl_attendance.attendance_status', array( '3', '4' ) );
  return $this->db->get()->result();
}

它將為您提供所需的用戶數據。

Answer 2

現在我明白了

public function get_manager_cordinator_users()
{
 $date=date('Y-m-d');
 $this->db->select('tbl_users.*');
 $this->db->join('tbl_account_details', 'tbl_users.user_id = tbl_account_details.user_id', 'left');
 $this->db->where('tbl_users.user_id NOT IN(SELECT user_id FROM tbl_attendance WHERE tbl_attendance.date_in= "'.$date.'" AND tbl_attendance.attendance_status IN (3,4) ) ');

 $this->db->where_in( 'tbl_account_details.designations_id', array( '2','3' ) );
 $this->db->where('tbl_users.banned', 0);
 $this->db->where('tbl_users.activated', 1);

 $query_result = $this->db->get('tbl_users');
 $result = $query_result->result();
 return $result;



}

Answer 3

用這個

     $this->db->select('tbl_account_details.*', FALSE);
     $this->db->select('tbl_users.*');
     $this->db->join('tbl_users', 'tbl_users.user_id = tbl_account_details.user_id', 'left');
     $this->db->where('(designations_id=2 or designations_id=3 )');
     $this->db->where('tbl_users.user_id NOT IN(SELECT user_id FROM tbl_attendance WHERE tbl_attendance.date_in='.$date.' && attendance_status=3 OR attendance_status=4 )');
     $query_result = $this->db->get('tbl_users');
     $result = $query_result->result();
     return $result;

Answer 4

$this->db->select('*)->from('tbl_users')->where('tbl_attendance.attendance_status <= 2')->where('tbl_attendance.data_in =',date('Ym-d '))->join('tbl_attendance','tbl_attendance.user_id = 'tbl_users.user_id','left')->get()->result();