[英]Sum of time for each user_id
好的,所以我有一個表,其中每個user_id
都有operation_timestamp
。 為了檢查每個user_id
采取了多長時間的操作,我使用查詢max(operation_timestamp)-min(operation_timestamp)
,然后將其轉換為小數,所以說得到以下結果:
SHIFT USER ID MIN MAX MAX-MIN DECIMAL
shift1 user_1 08:19:42 09:55:20 01:35:37 1.59
shift2 user_2 10:04:27 10:28:22 00:23:54 0.40
shift2 user_3 10:44:07 10:55:58 00:01:51 0.04
shift2 user_4 06:25:33 10:51:52 04:26:19 4.44
現在我的問題是: 如何計算出以小數表示的時間總和,以便使所有用戶花在活動上的總時間是多少? 像這樣:
SHIFT TOTAL_DECIMAL
shift1 1.59
shift2 4.88
我嘗試了相同的查詢,但沒有group by user_id
函數進行group by user_id
但是它隨后在不查看單獨的user_id的情況下計算了最大值和最小值,因此,可以說它會將shift2
總數計算為06:25:33 (user_4) to 10:55:58 (user_3)
,則結果以小數表示為4.45
。
這是我沒有成功使用的查詢:
select
case
when SUBSTR(a.operation_ts,12,13) between '00:00:00.000' and '05:59:59.000' then 'Nights'
when SUBSTR(a.operation_ts,12,13) between '06:00:00.000' and '13:59:59.000' then 'Days'
when SUBSTR(a.operation_ts,12,13) between '14:00:00.000' and '21:59:59.000' then 'Lates'
when SUBSTR(a.operation_ts,12,13) between '22:00:00.000' and '23:59:59.000' then 'Nights'
else 'other'
end as shift,
a.userid,
substr(min(a.operation_ts),11,9),
substr(max(a.operation_ts),11,9),
substr((max(a.operation_ts)-min(a.operation_ts)),10,9) as time_on_go,
round(((substr((max(a.operation_ts)-min(a.operation_ts)),11,2))*3600+(substr((max(a.operation_ts)-min(a.operation_ts)),14,2))*60+(substr((max(a.operation_ts)-min(a.operation_ts)),17,2)))/3600,2) time_decimal
from dc_sys_common:user_operation a
where a.activity_code = 1012
and date(a.operation_ts) between today and today+1
and SUBSTR(a.operation_ts,12,9) between '00:00:00' and '21:59:59'
group by userid, shift
having max(a.operation_ts)-min(a.operation_ts)>'0 00:00:01.000'
order by shift asc
使嵌套的第一個查詢的GROUP BY SHIFT:
SELECT `SHIFT`, SUM(`DECIMAL`)
FROM
(
-- your query here
)
GROUP BY `SHIFT`
我認為您需要進行兩個級別的聚合,一個級別在user_id
和shift
級別,第二個級別在shift
級別:
select shift,
from (select case when SUBSTR(a.operation_ts,12,13) between '00:00:00.000' and '05:59:59.000' then 'Nights'
when SUBSTR(a.operation_ts,12,13) between '06:00:00.000' and '13:59:59.000' then 'Days'
when SUBSTR(a.operation_ts,12,13) between '14:00:00.000' and '21:59:59.000' then 'Lates'
when SUBSTR(a.operation_ts,12,13) between '22:00:00.000' and '23:59:59.000' then 'Nights'
else 'other'
end) as shift,
a.userid,
round(((substr((max(a.operation_ts)-min(a.operation_ts)),11,2))*3600+(substr((max(a.operation_ts)-min(a.operation_ts)),14,2))*60+(substr((max(a.operation_ts)-min(a.operation_ts)),17,2)))/3600,2
) time_decimal
from dc_sys_common:user_operation a
where a.activity_code = 1012 and
date(a.operation_ts) between today and today+1 and
SUBSTR(a.operation_ts,12,9) between '00:00:00' and '21:59:59'
group by userid, shift
having max(a.operation_ts)-min(a.operation_ts)>'0 00:00:01.000'
) us
group by shift asc;
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.