[英]SQL to find distinct multiple values
我有一個保存房間信息的表,除其他外,其中包含BLDGCODE列和COSTCODE列。 建築物中的每個房間(BLDGCODE)只能分配一個成本代碼,並且這些成本代碼可以全部相同或不同。
我正在嘗試編寫一個腳本,該腳本僅顯示為多個房間分配了多個不同成本代碼的建築物,例如,多個房間可能具有成本代碼ABC,而其他一些房間可能要標識999並進行報告。 我已經嘗試過以下方法,認為CTE可以為我提供結果,但是我仍然看到只有一個成本代碼的建築物在建築物中的多個房間重復。
with CTE
as (
select rtrim(fmb0.reg_code) as Region,
rtrim(Country) as Country,
rtrim(fmb0.BLDGCODE) as BLDGCODE,
(
case
when FMB0.BLDGSTATUS = 'CAD'
then 'Yes'
else 'No'
end
) as CAD,
group_ as GROUP_,
fma0.usable,
fmb0.nia,
fmb0.niahprev
from fmb0
left join fma0 on fmb0.bldgcode = fma0.bldgcode
left join fmey on fmb0.propsubtyp = fmey.ey_key
left join fme2 on fmb0.country = fme2.descrip
where fme2.is_live = 1
and fmey.bau = 1
and fmb0.bldgcode not like 'xx%'
and fma0.bldgcode like 'cn%'
)
select CTE.Region,
CTE.Country,
CTE.BLDGCODE,
CTE.GROUP_,
sum(cte.usable) as AREA,
cte.nia,
cte.niahprev,
CTE.CAD
from CTE
where CTE.CAD = 'No'
group by CTE.BLDGCODE,
cte.group_,
cte.country,
cte.region,
cte.nia,
cte.cad,
cte.niahprev
having count(CTE.GROUP_) > 1
order by 1, 2, 3
我如何刪除那些盡管發生了多次卻成本代碼相同的建築物,而僅顯示那些具有多個成本代碼且其中不同的建築物?
因此,這里是引用單個表的代碼:
with CTE as (
select
rtrim(fma0.BLDGCODE) as BLDGCODE,
group_ as GROUP_,
fma0.usable
from fma0
where
fma0.bldgcode like 'cn%'
)
select
CTE.BLDGCODE,
CTE.GROUP_ AS COSTCODE,
sum(cte.usable) as AREA
from CTE
group by CTE.BLDGCODE, cte.group_
having count(CTE.GROUP_) > 1
order by 1
示例數據集為:
RMID BLDGCODE COSTCODE AREA
01.01 01 AA-01 10
01.02 01 AS-05 20
01.03 01 XY-99 30
01.04 01 XY-99 70
02.01 02 AA-01 10
02.02 02 AA-01 20
02.03 02 AA-01 20
預期結果將是:
BLDGCODE COSTCODE AREA
01 AA-01 10
01 AS-05 20
01 XY-99 100
BLDGCODE 02將不會顯示,因為它只有一個成本代碼
謝謝
你希望所有那些擁有多個costcodes行,因此一個簡單的聚集不起作用。 你可以做的另一種利用熱膨脹系數相同的邏輯和窗代替骨料:
with CTE as (
select
rtrim(fma0.BLDGCODE) as BLDGCODE,
group_ as GROUP_,
fma0.usable
from fma0
where fma0.bldgcode like 'cn%'
)
,counts as
(
select
CTE.BLDGCODE,
CTE.GROUP_ AS COSTCODE,
sum(cte.usable) as AREA,
case when min(CTE.GROUP_) over (partition by CTE.BLDGCODE)
<> max(CTE.GROUP_) over (partition by CTE.BLDGCODE)
then 1
else 0
end as flag
from CTE
group by CTE.BLDGCODE, cte.group_
)
select *
from counts
where flag = 1
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