iOS 私有 API：從后台喚醒應用程序

Question

我需要一個演示應用程序，它會在計時器事件時從后台喚醒自己。 使用私有API可以不越獄嗎？ 試過這個代碼：

void* sbServices = dlopen(SBSERVPATH, RTLD_LAZY);
int (*SBSLaunchApplicationWithIdentifier)(CFStringRef identifier, Boolean suspended) = dlsym(sbServices, "SBSLaunchApplicationWithIdentifier");
int result;
result = SBSLaunchApplicationWithIdentifier(CFSTR("com.my.app"), false);
dlclose(sbServices);

沒用

Answer 1

最后我找到了一個使用私有 api 的解決方案。 這是每 10 秒啟動自定義應用程序的示例代碼

@interface PrivateApi_LSApplicationWorkspace

- (bool)openApplicationWithBundleID:(id)arg1;

@end

@implementation ViewController {
    PrivateApi_LSApplicationWorkspace* _workspace;
}

- (void)viewDidLoad {
    [super viewDidLoad];
    _workspace = [NSClassFromString(@"LSApplicationWorkspace") new];

    NSTimer *timer = [NSTimer timerWithTimeInterval:10.0 repeats:YES block:^(NSTimer * _Nonnull timer) {
        [self openAppWithBundleIdentifier:@"com.app.my"];
    }];
    [[NSRunLoop mainRunLoop] addTimer:timer forMode:NSDefaultRunLoopMode];

}

- (BOOL)openAppWithBundleIdentifier:(NSString *)bundleIdentifier {
    return (BOOL)[_workspace openApplicationWithBundleID:bundleIdentifier];
}

@end