Javascript / jQuery組和排序組

Question

我目前有一系列由我們的MVC應用程序生成的div。 我試圖通過各種“數據 - ”屬性進行排序。 我能夠通過名為“data-categoryname”的屬性對項目進行分組。

每個項目還有一個'data-categorysortorder'，我想在其中按照排序順序值對'data-categoryname'創建的組進行排序。

我有一個JS Fiddle啟動，並將分組分組，我現在需要幫助按類別名稱按“類別排序順序”對組進行排序。 任何幫助表示贊賞。

https://jsfiddle.net/c0fawcnf/9/

//CURRENTLY HAVE GROUPING BY CATEGORY ITEM NAME AND WRAPPING EACH GROUP BY CATEGORY NAME, BUT NOW NEED TO SORT EACH CATEGORY WRAPPER BY THE ITEMS 'data-categorydisplayorder'

var $item = $('.item-box'),
   items = {};

$item.each(function () {
    items[$(this).data('categoryitemname')] = '';
});

for (category in items) {
    var categoryLowerCase = category.toLowerCase();
     $item.filter('[data-categoryitemname=' + category + ']').wrapAll('<div id="' + categoryLowerCase + '" class="categoryWrapper" data-wrappercategorydisplayorder="NEED_CATEGORY_DISPLAY_VALUE_HERE_AND_SORT_BY_THIS_VALUE"></div>');
    //return list;
    $('div#' + categoryLowerCase + '').prepend('<div class="page-title"><h1>' + category.replace("-", " ") + '</h1></div>');
}


// THESE ITEMS ARE OUTPUTTED BY AN MVC APPLICATION TO THE UI - I NEED TO SORT ON THE CLIENT SIDE BASED ON PARAMETERS

<div class="item-box" data-categoryitemname="Fall" data-itemsortorder="2" data-categorydisplayorder="2">Fall Item</div>
<div class="item-box" data-categoryitemname="Fall" data-itemsortorder="0"  data-categorydisplayorder="2">Fall Item</div>
<div class="item-box" data-categoryitemname="Fall" data-itemsortorder="1"  data-categorydisplayorder="2">Fall Item</div>

<div class="item-box" data-categoryitemname="Summer" data-itemsortorder="2"  data-categorydisplayorder="1">Summer Item</div>
<div class="item-box" data-categoryitemname="Summer" data-itemsortorder="1"  data-categorydisplayorder="1">Summer Item</div>
<div class="item-box" data-categoryitemname="Summer" data-itemsortorder="0"  data-categorydisplayorder="1">Summer Item</div>

<div class="item-box" data-categoryitemname="Winter" data-itemsortorder="2"  data-categorydisplayorder="3">Winter Item</div>
<div class="item-box" data-categoryitemname="Winter" data-itemsortorder="1"  data-categorydisplayorder="3">Winter Item</div>
<div class="item-box" data-categoryitemname="Winter" data-itemsortorder="0"  data-categorydisplayorder="3">Winter Item</div>

<div class="item-box" data-categoryitemname="Spring" data-itemsortorder="1"  data-categorydisplayorder="0">Spring Item</div>
<div class="item-box" data-categoryitemname="Spring" data-itemsortorder="2"  data-categorydisplayorder="0">Spring Item</div>
<div class="item-box" data-categoryitemname="Spring" data-itemsortorder="0"  data-categorydisplayorder="0">Spring Item</div>

我做了很多關於如何對項目進行排序的搜索，但是在已知元素中找到了很多已排序的元素，並且頁面上已存在一個ID。 由於我動態地將組添加到DOM，然后在創建組后進行排序，我還沒有真正找到關於如何做到這一點的任何內容。

更新：我得到了附加到組元素的排序順序值。 但我的排序功能仍然無法正常工作。 我更新了我的JS小提琴

https://jsfiddle.net/c0fawcnf/12/

// CURRENTLY HAVE GROUPING BY CATEGORY ITEM NAME AND WRAPPING EACH GROUP BY CATEGORY NAME, BUT NOW NEED TO SORT EACH CATEGORY WRAPPER BY THE ITEMS 'data-categorydisplayorder'

var $item = $('.item-box'),
   items = {};

$item.each(function () {
    items[$(this).data('categoryitemname')] = '';
});

for (category in items) {
    var categoryLowerCase = category.toLowerCase();
     $item.filter('[data-categoryitemname=' + category + ']').wrapAll('<div id="' + categoryLowerCase + '" class="categoryWrapper" data-wrappercategorydisplayorder="NEED_CATEGORY_DISPLAY_VALUE_HERE_AND_SORT_BY_THIS_VALUE"></div>');
    //return list;
    $('div#' + categoryLowerCase + '').prepend('<div class="page-title"><h1>' + category.replace("-", " ") + '</h1></div>');

    // GET ITEM BOX DISPLAY ORDER PROPERTY AND ATTACH IT TO THE WRAPPER CATEGORY DISPLAY PROPERTY
    var elem = $('div#' + categoryLowerCase + ' .item-box');
    elem.parent().attr("data-wrappercategorydisplayorder", elem.data("categorydisplayorder"));
}


// ATTEMPT TO SORT - BUT NOT WORKING
$('.productCategoryWrapper').sort(sort_items).appendTo('#item-grid');

//IS THIS EVEN CORRECT?
 function sort_items(a, b) {
     console.log('we shall sort');
     return ($(b).data('wrappercategorydisplayorder')) < ($(a).data('wrappercategorydisplayorder')) ? 1 : -1;
}

Answer 1

解決了它

我需要它的方式。 萬一其他人有興趣。 這是解決方案。

https://jsfiddle.net/c0fawcnf/14/

HTML

  <!--THESE ITEMS ARE OUTPUTTED BY AN MVC APPLICATION TO THE UI - I NEED TO SORT ON THE CLIENT SIDE BASED ON PARAMETERS-->
<div id="item-grid">


   <div class="item-box" data-categoryitemname="Fall" data-itemsortorder="2" data-categorydisplayorder="2">Fall Item</div>
   <div class="item-box" data-categoryitemname="Fall" data-itemsortorder="0"  data-categorydisplayorder="2">Fall Item</div>
    <div class="item-box" data-categoryitemname="Fall" data-itemsortorder="1"  data-categorydisplayorder="2">Fall Item</div>

  <div class="item-box" data-categoryitemname="Summer" data-itemsortorder="2"  data-categorydisplayorder="1">Summer Item</div>
   <div class="item-box" data-categoryitemname="Summer" data-itemsortorder="1"  data-categorydisplayorder="1">Summer Item</div>
    <div class="item-box" data-categoryitemname="Summer" data-itemsortorder="0"  data-categorydisplayorder="1">Summer Item</div>

  <div class="item-box" data-categoryitemname="Winter" data-itemsortorder="2"  data-categorydisplayorder="3">Winter Item</div>
   <div class="item-box" data-categoryitemname="Winter" data-itemsortorder="1"  data-categorydisplayorder="3">Winter Item</div>
    <div class="item-box" data-categoryitemname="Winter" data-itemsortorder="0"  data-categorydisplayorder="3">Winter Item</div>

  <div class="item-box" data-categoryitemname="Spring" data-itemsortorder="1"  data-categorydisplayorder="0">Spring Item</div>
   <div class="item-box" data-categoryitemname="Spring" data-itemsortorder="2"  data-categorydisplayorder="0">Spring Item</div>
    <div class="item-box" data-categoryitemname="Spring" data-itemsortorder="0"  data-categorydisplayorder="0">Spring Item</div>

</div>

JAVASCRIPT

//CURRENTLY HAVE GROUPING BY CATEGORY ITEM NAME AND WRAPPING EACH GROUP BY CATEGORY NAME, BUT NOW NEED TO SORT EACH CATEGORY WRAPPER BY THE ITEMS 'data-categorydisplayorder'

    var $item = $('.item-box'),
       items = {};

    $item.each(function () {
        items[$(this).data('categoryitemname')] = '';
    });

    for (category in items) {
        var categoryLowerCase = category.toLowerCase();
         $item.filter('[data-categoryitemname=' + category + ']').wrapAll('<div id="' + categoryLowerCase + '" class="categoryWrapper" data-wrappercategorydisplayorder=""></div>');
        //return list;
        $('div#' + categoryLowerCase + '').prepend('<div class="page-title"><h1>' + category.replace("-", " ") + '</h1></div>');

   //GET ITEM BOX DISPLAY ORDER PROPERTY AND ATTACH IT TO THE WRAPPER CATEGORY DISPLAY PROPERTY
 var elem = $('div#' + categoryLowerCase + ' .item-box');
//Give the parent element the category display value that is on the child item.
 elem.parent().attr("data-wrappercategorydisplayorder", elem.data("categorydisplayorder"));

    }

  //SORT 
function sort_items(a, b) {
    console.log('we shall sort');
    var a1 = $(a).data('wrappercategorydisplayorder');
    var b1 = $(b).data('wrappercategorydisplayorder');
    return a1 < b1 ? -1 : 1;
}

var ff = $('.categoryWrapper').get().sort(sort_items);

$.each(ff, function(index, item){
    $(this).appendTo('#item-grid');
});

Answer 2

我假設你最終想要通過data-itemsortorder值對每個組中的項進行排序，然后首先創建一個函數，首先按categorydisplayorder然后按itemsortorder對所有項進行排序。

function sort_items(a, b) {
    var ai = $(a).data('categorydisplayorder');
    var bi = $(b).data('categorydisplayorder');
    if (ai < bi) {
        return -1;
    } else if (ai > bi) {
        return 1;
    } else {
        ai = $(a).data('itemsortorder');
        bi = $(b).data('itemsortorder');
        if (ai < bi) {
            return -1;
        } else if (ai > bi) {
            return 1;
        } else {
            return 0;
        }
    }
}

並創建一個容器元素來插入組

<div id="container"></div>

然后，用於排列分組和排序項的腳本是

var groups = [];
var groupcontainer;
var items = $('.item-box');
var sorted = items.get().sort(sort_items); 
$.each(sorted, function (index, item) {
    var group = $(item).data('categoryitemname');
    if (groups.indexOf(group) == -1) {
        groups.push(group);
        var title = $('<div></div>').addClass('page-title').html($('<h1></h1>').text(group));
        groupcontainer = $('<div></div>').addClass('categoryWrapper');
        groupcontainer.append(title);
        $('#container').append(container);
    }
    container.append(item);
});

參考小提琴