如何一次輸入多個float變量

Question

例如：（我知道這是錯誤的，我只需要找出正確的方法即可。）

x, y, z = float(input('Enter what you would like x, y, and z to be.'))

因此，他們將鍵入1 2 3並且將按相應順序分配每個變量。

Answer 1

input()返回一個字符串，因此您需要將其拆分：

>>> input('Enter what you would like x, y, and z to be: ').split()
Enter what you would like x, y, and z to be: 1.23 4.56 7.89
['1.23', '4.56', '7.89']

...然后將每個結果字符串轉換為float ：

>>> [float(s) for s in input('Enter what you would like x, y, and z to be: ').split()]
Enter what you would like x, y, and z to be: 9.87 6.54 3.21
[9.87, 6.54, 3.21]

...此時您可以將結果分配給x ， y和z ：

>>> x, y, z = [float(s) for s in input('Enter what you would like x, y, and z to be: ').split()]
Enter what you would like x, y, and z to be: 1.47 2.58 3.69
>>> x
1.47
>>> y
2.58
>>> z
3.69

當然，如果用戶輸入了錯誤的浮點數，則會遇到問題：

>>> x, y, z = [float(s) for s in input('Enter what you would like x, y, and z to be: ').split()]
Enter what you would like x, y, and z to be: 12.34 56.78
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: not enough values to unpack (expected 3, got 2)

...所以處理它可能是一個好主意：

>>> while True:
...     try:
...         x, y, z = [float(s) for s in input('Enter what you would like x, y, and z to be: ').split()]
...     except ValueError:
...         print('Please enter THREE values!')
...     else:
...         break
... 
Enter what you would like x, y, and z to be: 1 2 3 4 5
Please enter THREE values!
Enter what you would like x, y, and z to be: 6 7
Please enter THREE values!
Enter what you would like x, y, and z to be: 8 9 0
>>> x
8.0
>>> y
9.0
>>> z
0.0