基於MAX（Column Name）從多個表中選擇和連接行

Question

總體而言，我的目標是從三個表中獲取客戶的電子郵件，代碼和最近的獎勵余額。

這三個表是：客戶，客戶代碼和獎勵

這些表大致如下所示...

顧客

id   email           lastcode
----|---------------|-----------
000 |test@test.com  | 1234test
001 |test1@test.com | 5678test
002 |test2@test.com | test1234
003 |test3@test.com | test5678

CustomerCode

id   code      customer
----|---------|---------
100 |1234test | 000
101 |5678test | 001
102 |test1234 | 002
103 |test5678 | 003

獎勵

customercode  logdate      balance
-------------|------------|--------
100          | 01/01/2016 | 1200
101          | 04/05/2016 | 40
102          | 06/22/2016 | 130
102          | 10/14/2016 | 220
103          | 12/03/2016 | 500
103          | 01/18/2017 | 750

我正在嘗試從鏈接回客戶的所有表中收集信息。 我目前正在使用以下SQL查詢，但遇到了一些問題。

SELECT Customer.email, Customer.lastcode, CustomerCode.id, Rewards.balance, MAX(Rewards.logdate)
FROM Customer
JOIN CustomerCode ON Customer.lastcode=CustomerCode.code
JOIN Rewards ON CustomerCode.id=Rewards.CustomerCode
GROUP BY Customer.Email, Customer.LastCode, CustomerCode.id, Rewards.Balance

結果

如您所見，我為同一位客戶獲得了多個結果，但我只想獲取每個客戶的最新獎勵余額。

email           lastcode    id    balance    logdate
---------------|-----------|-----|----------|-----------
test@test.com  | 1234test  | 100 | 1200     | 01/01/2016
test1@test.com | 5678test  | 101 | 40       | 04/05/2016
test2@test.com | test1234  | 102 | 130      | 06/22/2016
test2@test.com | test1234  | 102 | 220      | 10/14/2016
test3@test.com | test5678  | 103 | 500      | 12/03/2016
test3@test.com | test5678  | 103 | 750      | 01/18/2017

有什么方法可以消除這些重復的記錄，而僅顯示最近的獎勵余額？

Answer 1

您可以為此使用關聯的子查詢或聚合：

SELECT c.email, c.lastcode, cc.id, r.balance, r.logdate
FROM Customer c JOIN
     CustomerCode cc
     ON c.lastcode = cc.code JOIN
     Rewards r
     ON cc.id = r.CustomerCode JOIN
     (SELECT r.CustomerCode, MAX(r.logdate) as max_logdate
      FROM Rewards r
      GROUP BY r.CustomerCode
     ) rr
     ON rr.CustomerCode = r.CustomerCode AND rr.max_logdate = r.logdate;

Answer 2

像這樣嗎？

SELECT
  costumer.email,
  costumer.lastcode,
  reward.costumercode,
  reward.balance
FROM (SELECT DISTINCT
        rewards.costumercode,
        MAX(rewards.balance) as balance
      FROM rewards
      GROUP BY 1) AS reward
JOIN costumercode ON costumercode.id = reward.costumercode
JOIN costumer ON costumer.id = costumercode.costumer

它比Gordon的anwser更優化，並且更干凈。