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[英]Javascript : how inject a variable with html content to a data-attribute appended?
[英]How to pass dynamic data from html data-attribute to a query using javascript?
我有這個按鈕來保存數據庫中的數據
<button title="View Conversation" type='button' class='btn btn-default btn-sm' data-toggle='modal' data-target='#viewConversationModal'
data-empproj_id="<?=$employeeproject['emproj_id'];?>"
data-empprojconvoid="<?=$employeeproject['convofeed_id'];?>"
**data-empprojconvotoempid**="<?=$employeeproject['toemployee_id'];?>"
**data-empprojconvofromemip**="<?=$employeeproject['fromemployee_id'];?>"
data-empprojconvoconversation='"<?=$employeeproject['conversation'];?>"' >
</button>
我需要在查詢中使用數據
<?php
$toemployee = data-empprojconvotoempid
$fromemployee = data-empprojconvofromemip
$convoQ = "SELECT * FROM projects as p
JOIN employeeprojects AS ep ON p.project_id = ep.project_id
JOIN employees AS e ON ep.employee_id = e.employee_id
JOIN clients AS c ON p.client_id = c.id
JOIN employeeprojects_conversation AS epc ON ep.employee_id = epc.toemployee_id
WHERE epc.toemployee_id=**$toemployee** AND epc.fromemployee_id=**$fromemployee**";
$displayConvoResult=mysqli_query($db, $convoQ);
;?>
然后做一會兒陳述以模態顯示對話
<?php while($conversation=mysqli_fetch_array($displayConvoResult)){ ?>
<div class='row convorow'>
<div class='col-md-6 pull-left'>
<p style="font-size: smaller;">Messenger A :</p>
<textarea readonlyrows="4" cols="50"></textarea>
</div>
<div class='col-md-6 pull-right'>
<p style="font-size: smaller;">Messenger B :</p>
<textarea readonlyrows="4" cols="50"></textarea>
</div>
</div>
<?php } ;?>
到目前為止的腳本
$('#viewConversationModal').on('show.bs.modal', function(con){
var button = $(con.relatedTarget);
//get data
var empprojconvotoempid = button.data('empprojconvotoempid');
var empprojconvofromemip = button.data('empprojconvofromemip');
});
為了清楚起見:
現在,要將數據從前端發送到服務器,您可以執行以下操作:
$("button").click(_ => {
const me = $(this)
$.ajax({
url: window.location,
method: "post",
contentType: "application/json",
data: {
empprojToId: me.attr("data-empprojconvotoempid"),
empfromEmIp: me.attr("data-empprojconvofromemip"),
},
})
})
在您的情況下,您寧願讓按鈕執行正常的發布,並使用模態對話和新對話再次渲染整個頁面?
如果是這樣,則可以將所有數據以html格式放置:
<form method="post">
<input name="empproj_id" value="<?=$employeeproject['emproj_id'];?>">
...
<button type="submit">
</form>
<!--Insert Modal Code here-->
您應該將數據從html發送到php。 由於html在客戶端(在瀏覽器中)運行,而php文件在服務器端執行。
PHP手冊: http : //php.net/manual/en/reserved.variables.get.php http://php.net/manual/en/reserved.variables.post.php
最簡單的方法,使用jQuery:
<button id='buttonWithData' {data-attributes}></button>
<script type='text/javascript'>
var data = $('#buttonWithData').data();
$.ajax('urlOfYoursPhpFile', {
async: false,
data: data
});
</script>
然后,您可以使用GET
數組在php文件中捕獲數據。
注意使用GET和POST數組的SqlInjection。
使用jquery選擇器從屬性獲取數據,然后通過ajax發送數據。 var dataarray += $("button").attr ("data-...")
獲取數組或變量中的所有數據,然后獲取$.ajax ({ data: {"attrdata" : dataarray} , type: "POST",target="callback.php", sucess: function (data){ $("#modal").html(data);} });
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